1. Figure Q1 shows members ABD and CDE which are pin-jointed at D to form a structure to hold a total of 4 kN load. Cable BC is used to complete the structure. a) Sketch the free body diagram for the whole structure and determine the reactions at A and E. b) Sketch the free body diagram for members ABD and CDE and determine the reactions at B, C and D. c) Determine the internal normal force, shear force, and bending moment at sections a-a and b-b.

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.3.20P: A plane Frame is restrained at joints A and D, as shown in the figure. Members AB and BCD are pin...
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1. Figure Q1 shows members ABD and CDE which are pin-jointed at D to form a
structure to hold a total of 4 kN load. Cable BC is used to complete the structure.
a) Sketch the free body diagram for the whole structure and determine the
reactions at A and E.
b) Sketch the free body diagram for members ABD and CDE and determine
the reactions at B, C and D.
c) Determine the internal normal force, shear force, and bending moment at
sections a-a and b-b.
2 kN
to
1 m
1m -
2 kN
450
A
B
1.5 m
0.75 m
E
0.5 m
|D
a
1 m
- 1 m
1 m
Figure Q1
[Ans: a) FA = 2 kN, FE = 2 kN; b) FB = Fc= 2 kN, Fp = 2 kN; c) Na-a = 0 N, Va-a = 2 kN,
Ma-a = 1 kN.m; Np-b = 0 N, Vb-b= 0 N, Mp-b= 2 kN.m]
%3D
Transcribed Image Text:1. Figure Q1 shows members ABD and CDE which are pin-jointed at D to form a structure to hold a total of 4 kN load. Cable BC is used to complete the structure. a) Sketch the free body diagram for the whole structure and determine the reactions at A and E. b) Sketch the free body diagram for members ABD and CDE and determine the reactions at B, C and D. c) Determine the internal normal force, shear force, and bending moment at sections a-a and b-b. 2 kN to 1 m 1m - 2 kN 450 A B 1.5 m 0.75 m E 0.5 m |D a 1 m - 1 m 1 m Figure Q1 [Ans: a) FA = 2 kN, FE = 2 kN; b) FB = Fc= 2 kN, Fp = 2 kN; c) Na-a = 0 N, Va-a = 2 kN, Ma-a = 1 kN.m; Np-b = 0 N, Vb-b= 0 N, Mp-b= 2 kN.m] %3D
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