1. Consider the given logic equation below. Draw the logic diagram then sirmplify it using Boolean algebra. Draw the logic diagram based on the símplified logic equation. X = A'B'C' + A'B°C' + A'B°C* + A°B'C' + A'B°C*
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- A three input logic functipn will provide a logic high output only when twp (and two only) of the inputs are logic highs. For all other input possibilities, a logic zero is provided on the output. What is the logic expression? A. Y=A'B'C+A'BC'+AB'C' B. Y=AB'C+A'BC+ABC' C. Y=AB'C+ABC+A'B'C' D. Y=ABC'+AB'C+A'B'C'Task 6: Simplifying Boolean functions in EWB using the logic converter Simplify the following Boolean expression in EWB using the logic converter F (A, B, C) = AB'C'+ A'B'C'+ A'BC'+ A'B'CA three input logic function will provide a logic high output only when all of the inputs are logic highs or when all of the inputs are logic lows. For all other input possibilities, a logic zero is provided on the output. What is the logic expression? A. A'B'C'+AB'C' B. Y=A'B'C'+ABC C. ABC'+AB'C D. A'B'C'+AB'C
- Simplify the following expression using Karnaugh map and implement. Draw simplified logic diagram as well. Implement on Multisim software. (a) Y=A.B.C'.D+A.B'.C'.D+A'.B'.C'.D+A'.B.C'.D+A'.B'.C'.D'+A'.B.C'.D'+A'.B.C.D'+A'.B.C.D+A'.B'.C.DBasic Combinational Logic Circuits 2. Write the output expression for logic circuit: A B B XDesign the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).
- Draw the logic circuits for the following Boolean expressions and simplify the logic expressions using theorems of Boolean algebra. (Ā+B)(A+ Ē + D)D2.1 Combinational logic circuits. Tabulates a truth table for the following Boolean expression shown in Equation 1.1. f = A.B.C + A.B.C + A.B.C (1.1) 2.2 Half adder. A half adder is a circuit that adds two binary digits, A and B. It has two outputs, sum (S) and carry (C). The carry signal represents an overflow into the next digit of a multi-digit addition. Figure 1.2 depicted a logic diagram for a half adder. a. derives the Boolean expression for s and c. b. tabulates a truth table for the half adder. Ao Bo Figure 1.2: Half adder os S CConsider the given logic equation below. Draw the logic diagram then simplify it using Boolean Algebra. Draw the logic diagram based on the simplified logic equation. X = A'BC' + A'B'C' + AB'C + AB'C' + A'B'C From the given logic diagram, trace the output using all possible input combination. Give it a conclusion upon completion..
- Q.No.10: Draw Combinational Logic Circuit for the following Boolean expression i.e. one combine circuit for each expression? *Then simplify and prove the problems i.e. Boolean expression using Boolean rules and laws as discussed in the class. E.g. prove it with the help of Boolean rules and law that B+BC=B, how? (i) B+BC=B (ii) B+BC=B+C (iii) (B+C)(B+D)=B+CDDraw the equivalent logic circuit diagram of the following expressions : a. XY = F b. X + Y = F XÝZ = F c. d. XY + XZ = F e. XYZ + XÝZ = FWrite the Boolean expression for the logic circuit in Figure 5. Simplify the Boolean expression using DeMorgan’s Theorem and Boolean algebra rules and laws. Show the steps of your simplification below. simplify curcuit