1. Briefly explain why water is considered as the universal solvent. 2. Using the concept of IMFA, account for the difference in boiling point and melting point of the following molecular substances: Substance Boiling point (0C) Melting point (°C) Helium gas, He -269 -272 Methane, CH4 -162 -184 HO 100 Ethanol, CHOH 78 -117

1. Briefly explain why water is considered as the universal solvent. 2. Using the concept of IMFA, account for the difference in boiling point and melting point of the following molecular substances: Substance Boiling point (0C) Melting point (°C) Helium gas, He -269 -272 Methane, CH4 -162 -184 HO 100 Ethanol, CHOH 78 -117

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter16: Applications Of Neutralization Titrations

Section: Chapter Questions

Problem 16.3QAP

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Consider the following information: Ksp(BasO4) = 1.1 x 10-10 Ksp(CasO4) = 4.9 x 10-5 Ksp(PbSO4) = 2.5 x 10-8 Ksp(Cd(OH)2) = 2.5 x 10-14 Ksp(Cr(OH)3) = 1.6 x 10-44 These compounds arranged in order of increasing aqueous solubility is a. PBSO4 < Cd(OH)2 < BaSO4 < Cr(OH)3 Ob. Cr(OH)3 < Cd(OH)2 < BasO4
Consider the following information: Ksp(BasO4) = 1.1 x 10-10 Ksp(CaSO4) = 4.9 x 10-5 Ksp(PbSO4) = 2.5 x 10-8 Ksp(Cd(OH)2) = 2.5 x 10-14 Ksp(Cr(OH)3) = 1.6 x 10-44 These compounds arranged in order of increasing aqueous solubility is a. Cd(OH)2 < CasO4 < PbSO4 < BaSO4 O b. Cd(OH)2 < Baso4 < PBSO4 < CaSO4 O. Cd(OH)2 < Cr(OH)3 < BaSO4
Answer Bank Record mass.
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