1. Benzene reacts with bromine to form bromobenzene, C6H5Br. C6H6(1) + Br2(1) ->>> C6H5Br(1) + HBr(g) (a) What is the maximum amount of C6H5Br that can be formed from the reaction of 7.50 g of C6H6 with excess Br2 ? (b) A competing reaction is the formation of dibromobenzene, C6H4Br2. C6H6(1)+2Br2(1) → C6H4Br2(1) + 2HBr(g) If 1.25 g of C6H4Br2 was formed by the competing reaction, how much C6H6 was not converted to C6H5Br?

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