1. (5) Run the following program where PC starts from memory address 100 A Program address 100 101 102 800 801 802 memory address 800 contents: 2. (5) Run the following program where PC starts from 210 address 210 211 212 800 Question: 1) Upon the completion of the program, what will be the contents of the following memory address? 801 802 0028H memory address 800 contents: . Memory contents 5800 1801 6800 OOOE 000A 0005 Memory 000A-0005 contents Answer all questions with hexadecimal. 5800 2801 6800 001E 000A 000C Question: 2) Upon the completion of the program, what will be the contents of the following memory address? A Program new contents

1. (5) Run the following program where PC starts from memory address 100 A Program address 100 101 102 800 801 802 memory address 800 contents: 2. (5) Run the following program where PC starts from 210 address 210 211 212 800 Question: 1) Upon the completion of the program, what will be the contents of the following memory address? 801 802 0028H memory address 800 contents: . Memory contents 5800 1801 6800 OOOE 000A 0005 Memory 000A-0005 contents Answer all questions with hexadecimal. 5800 2801 6800 001E 000A 000C Question: 2) Upon the completion of the program, what will be the contents of the following memory address? A Program new contents

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter3: Assignment, Formatting, And Interactive Input

Section3.4: Program Input Using Cin

Problem 9E

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AIM- Write an 8085 sequence to check whether the first set of reading is higher than the second one or not. PROBLEM STATEMENT- The pressure of two boilers is monitored and controlled by a microcomputer works based on microprocessor programming. A set of 6 readings of first boiler, recorded by six pressure sensors, which are stored in the memory location starting from 2050H. A corresponding set of 6 reading from the second boiler is stored at the memory location starting from 2060H. Each reading from the first set is expected to be higher than the corresponding position in the second set of readings. Write an 8085 sequence to check whether the first set of reading is higher than the second one or not. If all the readings of first set is higher than the second set, store 00 in the 'D' register. If any one of the readings is lower than the corresponding reading of second set, stop the process and store FF in the register 'D'. Data (H): First set: 78, 89, 6A, 80, 90, 85 Second Set:71, 78,…
13) Write a subroutine subprogram to calculate the value of a factorial number, use this subprogram in a main program to calculate the value of F: F16= 5!+ 7! +9!+ ..+15! . Store the result in memory locations starting at address (DS: 3000). 14) Write a subroutine subprogram to calculate the square of two hexadecimal numbers, use this subprogram in a main program to calculate the value of Y: Yj0=(15)²+(50)²+(17)? Store the result in memory locations starting at address (DS: 4000). 15) Write an 8086 assembly program to count the numbers of (0's) in the following byte: (11011010),
13) Write a subroutine subprogram to calculate the value of a factorial number, use this subprogram in a main program to calculate the value of F: F16= 5!+ 7! +9!+ ...+15! . Store the result in memory locations starting at address (DS: 3000). 14) Write a subroutine subprogram to calculate the square of two hexadecimal numbers, use this subprogram in a main program to calculate the value of Y: Y10=(15)²+(50)²+(17)² Store the result in memory locations starting at address (DS: 4000). 15) Write an 8086 assembly program to count the numbers of (0’s) in the following byte: (11011010), 16) For the circuit that is shown in the Figure shown below. LG represent logic circuit with the following function: Y= N1.N2+ (N1+N2) Write a subroutine (subprogram) to implement the function of LG, use this subprogram in main program to find the value of M for the following values: X1=0, X2=1, X3=1, X4=1, X5=1 X1 LG X2 N1 Y LG X3 M N2 X4 LG X5
5. Write an assembly language program that inputs the number of a student from the keyboard and after the entry, it displays the number at the centre of the text screen in vertical manner. For example, if you enter your student number as 87138 it will be displayed at the centre of the monitor in the following way: 8 7 1 3 8 Hints: INT 21H, AH= 0AH inputs a string of data from the keyboard. The interrupt requires that the offset address of the buffer is in DX. INT 21H, AH= 02 outputs a character to the monitor and assumes the character in DL (ASCII). INT 10H, AH= 02 sets cursor location and assumes row in DH and column in DL.
The following tables contains memory dump and contents of few registers, as follows: *** add cont reg cont Ox100 OXFF eax 0x100 Ox104 OXCD есх Ох1 Ox108 Ox22 edx 0x3 Ох10С Ох33 **** What is the value of the following operand 9[eax,edx] ? Select one: а. Ох103 b. Ox09 с. Ох33 d. 0x10C
Homework 4 Solution should use this website for solution Sim8085 - A 8085 microprocessor simulator Question 2 Write a program to perform the operation: Multiply by 2. Assume the input data is stored in a half a byte at location 20D0h.The format of the input is 0000X3X,X¡Xo. As an example, the data value can range from 00 to OF. The output should be stored at 3000h
i) Suppose you have an Intel 8086 Microprocessor which is running at a frequency of 5 Hz. Now what is the maximum number of times it can read a byte of data from the memory in 4 seconds? 5000000 O 50000 500 O5 ii) there can be multiple answer in this checkbox.please check all Suppose an Intel 8086 Microprocessor is operating at 9 MHz. Which of the following statements are true? OThe clock cycle is 111.11 ns OIn each bus cycle, the clock remains high for 36.67 ns OData is supplied during the 222.22 ns to 333.33 ns period in a bus cycle. OThe Status Bus bits become available before 222.22 ns in a bus cycle. OWhile reading, ALE stays high during the 111.11 ns to 222.22 ns period in a bus cycle.
* The LOOP # will affect only CX O All CS, CX and IP Both CX and IP non of those only IPO if BX=1000, DS=0400, and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL. the physical address is 6243H O 6324H 4244H O 6234H 4234H
1. Show the program execution for the following program.The hypothetical machine has four (4) opcodes:1110 = LOAD0111 = STORE1000 = ADD i) LOAD AC from memory location 806. The content of this location is 5.ii) ADD the content of memory location 807. The content of this location is 5.iii) STORE the content of AC to memory location 901. Assume that a value of 300 is the starting value contained in PC.
a) Please fill in the blanks A: .word 1536 768 384 #load the address of A to $s0 #load A[2] into to $te, $to, 2 #load A[0] into t1 sll sub srl $a0, $t1, $t0 $t1, $t1, 1 #load A[1] into t2 sub $al, $t1, $t2 What is in $a0 and $a1? Please explain. b) Please express the values in the array A in binary (16 bit representation) and hexadecimal
Please write the lines that the code will print out. Assume the following addresses: - a in main has the address 1000-b in main has the address 1004 c in main has the address 1008 - d in main has the address 1012 - b in fooA has the address 2000 - a in fooA has the address 2008 int fooA (int* b, int& c, int a) { (*b) ++; c+ = 2; a + = 4; cout <<<<<<' <<<&Q<<< ""«a« ""<< b<< "" <<
Weight 2. A BMI (body mass index) is roughly weight over height square (BMI : Height2 Write Assembly code to calculate average BMI of N students. Relevant data is stored in memory as shown in the example below. Address 10 has the total number of students (N) followed by N weights and heights. Store the computed average BMI at the address 70. For example, if N = 2, the memory contents will be as follows: 0 1 2 |3 | 4 |5 6 10 02 96 05 5A | 06 There are 2 records. Weight and height of the 1s person is 96 and 05 respectively. Similarly, 5A and 06 are the weight and height of the second person. Assume decimal points are ignored and the average will be a rounded integer value. All divisions are integer divisions as well. Please use the Instruction Set of the simulator discussed in class. (http://www.softwareforeducation.com/sms32v50/sms32v50_manual/245-IsetSummary.htm)