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- int j; for (int i = 0; i < 5; i++) {j = 2*j*i;} What is j?CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;Q1/ find code optimization of this code then find type to this code. for (i=1;i#include using namespace std; const int y = 1; int main () { int static y = 2; int i = 3, j = 4, m = 5, n = 6; %3D int a = [] (int x, int i = 1) { return x * i; } (y, 3) ; %3D int b = [=] (int x) { return [=] (int b) { return b + j; } (x) % 7; } (a); int c = [=] (int x) mutable ->int { m = 6; return [6] (int j) mutable { y = a * b; return y / j; } (x) -m; } (b) ; cout << a << endl; cout << b << endl; cout << c << endl; cout << m << endl; cout << y < endl; return 0; This program outputs 5 lines. What are they? Please explain your work and your answer.int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;int fun(int k){ return ( ); void main(){ int n; cin >> n; n = n * fun(n); <-- 1 Fill in the appropriate statement and expression in fun, so that when it is called in main, and after the execution of the statement marked 1, the value of n would always be n3.def winning_card(cards, trump=None): Playing cards are again represented as tuples of (rank,suit) as in the cardproblems.pylecture example program. In trick taking games such as whist or bridge, four players each play one card from their hand to the trick, committing to their play in clockwise order starting from the player who plays first into the trick. The winner of the trick is determined by the following rules:1. If one or more cards of the trump suit have been played to the trick, the trick is won by the highest ranking trump card, regardless of the other cards played.2. If no trump cards have been played to the trick, the trick is won by the highest card of the suit of the first card played to the trick. Cards of any other suits, regardless of their rank, are powerless to win that trick.3. Ace is the highest card in each suit.Note that the order in which the cards are played to the trick greatly affects the outcome of that trick, since the first card played in the trick….“Dangling and wild pointers are known to be problems with pointers”. Justify the given statement with the helpof suitable examplevoid main (void) { char result = a; for (char i = { 10; i > 5; i = i-1) result = result + i; } // point B } Consider the code above. What is the decimal value of "result" at "point B" if the variable "a" is initially 59?[CLO-5] What is the value of the variable ss after the following code is executed? int x[ 7 ] = (5,10,3,0,-10,4); int ss=0; for (int i=1;i<=6; i++) { ss+=x[i]; cout<int f(int &k){k++;return k * 2;}int main(){int i = 1, j = -1;int a, b, c;a = f(i) + i/2;b = j + f(j) + f(j);c = 2 * f(j);return 0;} What are the values of a, b and c id the operands in the expressions are evaluated from left to right and then what are the values when its evaluated right to left?c) Indicate the line number, identify the errors and suggest solutions to fix the errors in the following code shown in Figure 1 below. 1 public class TestQ2 { public static void sum(int array){ 2 3 int total=0; for (int i=0; iSEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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