+ +1 30 V 120 V 10 Ω 15Ω + Vca(t)=L1 F =0.25 F + 10 Ω 10 V
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The circuit shown below has been in that situation for a long time. At t=0, part of the circuit is cut down from the dashed line. Determine vC1(t) for t > 0.
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- Find T 0.5 ms 40 92 www www 892 160 92 20 mH www+5V VDO EN Xtal 8ה 7 +5V Freq1 HGND | GND х Mhz Sensor0 crystal Freq26 5 Vss Out 04 PRE Xtal 1k Output HA7210IP 4 CLK CLR SN74HC7491 GND 0.01 μ GND +5V 4 +5V +5V +5V OE O/P3 0. 1µF | 47µF GND SG351P |2 x MHz GND GND Consider the Quartz Crystal Microbalance Sensor shown above, with crystal resonant frequency, x = 3.3 Mhz. You are given the following values: Active crystal area = 1.6 cm², and the change in frequency = - 10 Hz Calculate the change in mass, Am in nano gram, up to 2 decimal places. Answer:1 In an inductive circuit, What is the value of the instantaneous current if t=40 s ‚L- 1 0mH and v(t) = 50 cos(100nt - 100) | 15.9+170j -14.5+0j None of the answers -15.6+0j Moving to another question will save this response. MacBook Pro F3 F4 F5 F7 #3 $ 3r 48 50 67 7 V 8- 2R U. * 00
- For the circuit shown, what is the Norton equivalent current, IN? j3 N 12 0 2452.6° A -j5 N (+2) 14430° V O 3.08452.6° A O 3.29/39.5° A O 2.0252.6° A O 1.15/39.5° AIn the figure, ɛ = 12.0 V, the time constant is 500us, and Imax = 200 mA. What is L? %3D S L R A. 500 µH B. 2.75 mH C. 30.0 mH D. 1.20 H llQ1 (a) Based on electrical DC circuit as depicted in Figure Q1(a), (i) Determine the mesh currents I1, I, I3 and I4 by using mesh analysis. Then calculate the branch current, I. (ii) Calculate the power at 50 V voltage source and determine whether the power is supplied or absorbed by the voltage source. 4Ω 20V Iz 5Ω 50V Ia 10V O4A 50 N 20 2 52 Figure Q1(a) (b) Figure Q1(b) shows an AC circuit. Given the voltage, Va across the impedance Za is 111.803 2 - 41.57° V. (i) Determine the value of impedance Za. (ii) Determine the complex power, S, real power, P, reactive power, Q, apparent power, |S| and power factor of the circuit. (iii) Calculate the capacitor value needed to increase the circuit's power factor to 0.85.
- Question 6/12 Using source transformation, if V, 60V them v,is 1. OA 2. OB 3. OC 4. OD 5. OE 6. OF 7. OG 8. OH 32 ww ww 42 3 A ( 82 Vx A) 3.2V B) 9 €V C) 16V D) 22.4V E) 28.8V F1 352V G) 41.6V AB+ (H Previous NextFiring angle=50 Degree 1:2 oVo -200/200V 5 Ohm The PIV of the Thyristor greater or equal to : 50 Hz O 133.3V. O 346.4V O 287.6V O 200V O 800V O 400V O 100V Ne here to search F7 F8 F10 F11 #3 $4 3 4 5 6. V E 41 T Y 1O G y H i - K L C V BYNIMR1 3.3k2 Vi VD | 10V 60HZ 0° Vo Vt 3V If the input voltage Vi = 10V (peak to peak) a. Solve for output voltage Vo b. Solve for the voltage across the resistor R1 (VR1) c. Sketch the output waveform of the circuit Upload your solutions and answers
- In the circuit given below, what should be the minimum value of C1 capacitor so that this capacitor does not affect the circuit negatively when f = 800 Hz? (Aeegidaecilen devrede f Ensatorunn ceuele Cbp V1 0.1pF R2 3310 12V R4 C1 R3 U1 Vout vz LM358 PR1 SINE(O 50mV) 33K O a. 4,23 nF O b. 2.96 nF O. 10,59 nF O d. 6,78 nF O e. 5,51 nF O f. 9,32 nF O g. 8,05 nF O h. 11,86 nF0 !!! a *Further Engineering Mathematic X + File | C:/Users/user/Downloads/Further%20Engineering%20MathematicsAssignment-2.pdf Draw T Read aloud CD 9. The two complex numbers V and W represent two reactances connected in series. Calculate the total reactance by finding their sum. AF 3+j4 B = 4-j5 C = 5-j2 D=1-j3 E = 2 +j3FF" FF 4+j1 3 of 4 10. The complex numbers V and W represent two force vectors. Place them on an Argand diagram and calculate the difference between them. 11. Use your given values of V and W to represent the reactances Z₁, Z₂ (as shown in the circuit diagram). Calculate the current flowing in the circuit in polar form if the voltage is v = 1220° and V i = ZTotal Z₁ Z₂ o J (¹) ENG T 60 11:16 PM 3/17/2023 xThe zero and poles of the circuit are: 10mH 10μF 102 VOUT O Z = 0, p = x (-0.5 ± j3.1225) x 10³ O Z = 1, p = x (-0.05 ± j3.1619) x 103 O Z = 0, p = x (-0.005 ± j3.1623) x 10° O Z = 1, p = x (-0.5 ± j3.1225) x 103 None of the above.