1 0 2 1 0 0 4 3 -2 -1 1 [2 1 -2 -1] 1 2 2 2 3 2 3 5 1 3 4 2 A = Jl = 2 %3D 2 [4 -1 2 -4 -4 5 -3 -1 3 0 0 4 0 -4 2 0 -1 3 3 0 4 3 - -2 -4 A= 0 -3 2 -0.1 0 4 0 0 0 0 -3 3 4 The hand frame A is given. The corresponding inverse Jacobian of the robot at this location relative to this frame, its differential operator and its differential motions are also shown. Thus, compute the change in the hand frame A, and its new location after the differential motion.

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 12CR
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robotics question. Please answer ASAP.

1
2
1
[2
2
1
-2
-1
4
3.
-2
-1
1
A =
2
3
4
2
3
2
3.
%3D
2
[4
2
-4 -4
-1
-1
3
-3
-1
3
0.
4.
-4
0 2
1
4
3.
-1
-2
-4 0
-3
-0.1
A =
-3
3
4
The hand frame A is given. The corresponding inverse Jacobian of the robot at this location
relative to this frame, its differential operator and its differential motions are also shown. Thus,
compute the change in the hand frame A, and its new location after the differential motion.
Transcribed Image Text:1 2 1 [2 2 1 -2 -1 4 3. -2 -1 1 A = 2 3 4 2 3 2 3. %3D 2 [4 2 -4 -4 -1 -1 3 -3 -1 3 0. 4. -4 0 2 1 4 3. -1 -2 -4 0 -3 -0.1 A = -3 3 4 The hand frame A is given. The corresponding inverse Jacobian of the robot at this location relative to this frame, its differential operator and its differential motions are also shown. Thus, compute the change in the hand frame A, and its new location after the differential motion.
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