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- Implement boolean function f(A, B, C, D) =( 0,2,5,8,10, 14) B part :(A, B, C, D) =(2, 6,11)Simplify the following Boolean functions, using three-variable k-maps: a. F (x,y,z) = Σ(2,3,4,5) b. F (x,y,z) = Σ(0,2,4,6) c. F (x,y,z) = Σ(1,2,3,6,7) d. F (x,y,z) = Σ(1,2,3,5,6,7) e. F (x,y,z) = Σ(3,4,5,6,7)Correct answer will be upvoted else downvoted. Computer science. You are given three positive (more prominent than nothing) integers c, d and x. You need to track down the number of sets of positive integers (a,b) with the end goal that balance c⋅lcm(a,b)−d⋅gcd(a,b)=x holds. Where lcm(a,b) is the most un-normal various of an and b and gcd(a,b) is the best normal divisor of an and b. Input The primary line contains one integer t (1≤t≤104) — the number of experiments. Each experiment comprises of one line containing three integer c, d and x (1≤c,d,x≤107). Output For each experiment, print one integer — the number of sets (a,b) to such an extent that the above uniformity holds.
- I need help with this problem involving Boolean variables and I am absolutely lost on this problem since I never seen anything like it. If (f(w,x,y,z) = (x+yz) + (wx). What is f(1,0,0,0) There is a line over (x+yz), there is a line over letter z, and there is a line over letter w.Design a deterministic finite state automaton (DFA) that accepts exactly the strings over the alphabet {A, B, ...,Z} that contain at least two R, at most one T, and where every E comes after some S (there may be other letters in between). For instance, your DFA should accept the strings: • MYSTICWARRIORS • MARSMATRIX • SHOCKTROOPERS • CONTRAHARDCORPS STRIDER but not the strings • CRAZYTAXI (it does not contain at least two Rs) LASTRESORT (it contains more than one T) AFTERBURNER (there are Es without a S somewhere before them) • BATTLECIRCUIT (all of these at the same time) Clearly indicate the meaning of each state. One way to do this is to number the states and have a numbered list of their meanings, but any readable method you use to label and explain your states is fine. Hint: there are three separate conditions accepted strings must meet; states will need to encode whether or not each one is met (or perhaps partially met). You can label an edge with the word “else" to indicate it…Let N = {0, 1, 2, . . .} be the set of Natural Numbers. Given an n ∈ N, which of the followingconditions are necessary, and which of these conditions are sufficient, for the Natural Number,n, to be a factor of 10.(a) 1 is a factor of n.(b) 1 is a factor of 2n.(c) −n is a factor of 10.(d) 10 is a multiple of n.(e) n is divisible by 2.(f) n^2 is divisible of 5.(g) n = 10.
- C-F languages (or see the following figure). In particular..it points out that the language {am,a"b" | m,n = N} is a deterministic C-F language, but not LL(k) for any k Palindromes over {a, b} Non-deterministic C-F {am,a"b" | m.ne N}; Deterministic C-F -LL(K) {ab❘n EN}- Regular To show the language is not LL(k) for any k, note that a grammar for this language is SAB A→ B -> 10 or S-A|B A→ B (you only need to answer one case here, either one). The language contains A as an element. Now consider the case k = 1 and consider the input string ab. When the first symbol is scanned, we get an 'a'. This information alone is not enough for us to make a proper choice. So we don't even know what to do with the first step in | the parsing process. For k = 2, if we consider the input string aabb, we face the same problem. For any k > 2, the input string ab would cause exactly the same problem. So this grammar is not LL(k) for any k. On the other hand, by putting proper instructions into the blanks…Simplify the following Boolean functions, using K-maps: F (A, B, C, D)=?(1,3,6,9,11,12,14)Simplify the following Boolean function , using three- variable maps: a) F(x,y,z) = Σ (0,2,6,7) b) F(A,B,C ) = Σ (0,2,3,4,6) c) F(a,b,c) = Σ (0,1,2,3,7) d) F(x,y,z) = Σ (3,5,6,7)
- For the definition of x ∈ EXPR , na(x) denotes the number of a’s in the string, and we will use nop(x) to stand for the number of operators in x (the number of occurrences of + or ∗). Show that for every x ∈ EXPR, na(x)= 1 + nop(x).Q4// Simplify and then implement the Boolean function F(A,B,C,D) = N (1,2,3,5,6,7,9,11,13,15) using POS karnough map , draw the implementation. %3DFor which of the following is the set S equal to {(a, b)|a, b nonnegative integers }? Select one: O A. None of these. O B. (0,0) S; (x, y) = S → (x + y, y) = S and (x,x + y) = S O C. (0,0) = S; (x, y) = S→ (x + 1, y) = S and (x, y + 1) = S O D. (0,0) E S; (x, y) = S → (x + 1, y + 1) = S