In our first example, we will see that we can use alever arm to greatly increase the torque without havingto provide more force. Suppose, for instance, that anamateur plumber, unable to loosen a pipe fitting, slipsa plece of scrap pipe (sometimes called a "cheater")over the handle of his wrench, He then applies his fullweight of 900 N to the end of the cheater by standingon it. The distance from the center of the fitting to thepoint where the weight acts is 0.80 m, and the wrenchhandle and cheater make an angle of 19° with thehorizontal (Figure 1). Find the magnitude and directionFigureof 10.80 mF=900 N19" If the pipe fitting under consideration can withstand a maximum torque of 650 N- m withoutbreaking, what is the smallest angle at which our amateur plumber can safely stand on the end of thecheater and apply his full weight without breaking the pipe fitting?Express your answer in degrees.ΑΣφ

Answered: 0.80 m F=900 N 19

Science

Physics

0.80 m F=900 N 19

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter11: Angular Momentum

Section: Chapter Questions

Problem 49P: The blades of a wind turbine are 30 m in length and rotate at a maximum rotation rate of 20 rev/min....

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Question

In our first example, we will see that we can use a
lever arm to greatly increase the torque without having
to provide more force. Suppose, for instance, that an
amateur plumber, unable to loosen a pipe fitting, slips
a plece of scrap pipe (sometimes called a "cheater")
over the handle of his wrench, He then applies his full
weight of 900 N to the end of the cheater by standing
on it. The distance from the center of the fitting to the
point where the weight acts is 0.80 m, and the wrench
handle and cheater make an angle of 19° with the
horizontal (Figure 1). Find the magnitude and direction
Figure
of 1
0.80 m
F=
900 N
19"

If the pipe fitting under consideration can withstand a maximum torque of 650 N- m without
breaking, what is the smallest angle at which our amateur plumber can safely stand on the end of the
cheater and apply his full weight without breaking the pipe fitting?
Express your answer in degrees.
ΑΣφ

Expert Solution

Step 1

Force acting by plumber $F = 900 N$

The distance between the center and point of action = 0.80 m

maximum torque acting on pipe without breaking $τ = 650 N . m$

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