: For the amplifier shown in Figure 1, the BJT parameters are ß = 75, VeE(on) =0.7 V, VcE (sat) = 0.3 V, V = co, and V = 25 mv.27 k2Re22 kQ10 ka Ca2 k2Rg=12 KO15 KOFig. 1: The electronic circuit for question 4.i..; The value of the DC base current Ig is(A) 2.167 mA.(B) 0.0249 mA.(C) 2 mA.(D) 0.023 mA.· The value of the DC collector current Ie isii. .(A) 0.167 mA.(B) 0.0289 mA.(C) 2 mA.(D) 1.87 mA.iii. ."he value of the collector-emitter voltage Vcr is(A) 2.612 V.(B) 0.3 V.(C) 0.7 V.(D) 1.23 V.iv. (5 points) The AC voltage gain A, = is(A) -6.52.(B) -65.2.(C) -12.3.(D) -123.ww

Answered: Image /qna-images/answer/85bb39fa-997d-4853-ad97-f4781f3c8548.jpg

0.7 V, Vcr (sat) = 0.3 V,V = 0, and V = 25 mv. Vo9V Re 22 kO wwHE 2 k2 Rg 12 K0 Fig. 1: The electronic circuit for question 4. i.. ; The value of the DC base current I, is (A) 2.167 mA. (B) 0.0249 mA. (C) 2 mA. (D) 0.023 mA. ii... The value of the DC collector current /e is (A) 0.167 mA. (B) 0.0289 mA. (C) 2 mA. (D) 1.87 mA. ii. . (A) 2.612 V. (B) 0.3 V. (C) 0.7 V. "he value of the collector-emitter voltage Ver is (D) 1.23 V. iv. (5 points) The AC voltage gain A, = i (A) -6.52. (B) -65.2. (C) -12.3. (D) -123, ww

0.7 V, Vcr (sat) = 0.3 V,V = 0, and V = 25 mv. Vo9V Re 22 kO wwHE 2 k2 Rg 12 K0 Fig. 1: The electronic circuit for question 4. i.. ; The value of the DC base current I, is (A) 2.167 mA. (B) 0.0249 mA. (C) 2 mA. (D) 0.023 mA. ii... The value of the DC collector current /e is (A) 0.167 mA. (B) 0.0289 mA. (C) 2 mA. (D) 1.87 mA. ii. . (A) 2.612 V. (B) 0.3 V. (C) 0.7 V. "he value of the collector-emitter voltage Ver is (D) 1.23 V. iv. (5 points) The AC voltage gain A, = i (A) -6.52. (B) -65.2. (C) -12.3. (D) -123, ww

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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