only J, K, and L 2015E 104time ($)tim: (5)G. Two objects appear at the same place (15 cm) at 1 second, one disappears at 20 cm at 2 seconds whileanother appears at x = 0, both disappear at same location at 3 seconds. (Cannot reproduce withmotion sensor. Not a function.)H. Constant velocity of +2 cm/s, acceleration = zero, change in position = 10 cm.I.Constant acceleration+0.8 cm/s, initial velocity = 0 cm/s.3tine (5)time (s)tine (5)25.tina (s)Constant acceleration = -1 cm/s, initial velocity = +3 cm/s.tiae (5)J.K. Initial velocity = zero, acceleration is positive and increasing to about +1 cm/s/s.L. Initial velocity = zero. For first 2 seconds, acceleration =-2 cm/s, from 2-3 seconds, acceleration = +4cm/s; after t = 3 seconds, both velocity and acceleration are zero.%3DM. Acceleration is initially negative, changes to zero. Initial velocity = 4 cm/s, decreases to about -1.5cm/s.N. Initial velocity = 4 cm/s. Acceleration is initially negative, changes to zero by 3 seconds and remainszero. Final constant velocity = +1.5 cm/s.0. Initial velocity = -2 cm/s, is constant for first 2 seconds. Then there is a constant acceleration of+1.33 cm/s as velocity increases to 2 cm/s.() A3. 1.For each of the following graphs, discuss with your team and think of a motion that would create the graph.Be sure that you can accurately describe the velocity and acceleration for each motion.2.Your team will be assigned two motions. Write a detailed description of the motions, with enough detail sothat someone can follow your instructions and recreate the graph.2020201515151010100.0.23.5.1time (s)time (s)A. Constant position = 5 cm from origin. Velocity = 0, acceleration = 0.%3DB. Constant velocity = +2 cm/s, acceleration = 0, initial position = 5 cm.C. Constant velocity = -3 cm/s, acceleration = 0, initial position = 20 cm.D2020151515E 1010101.time (s)0.time (s)time (s)D. Velocity changes from 0 to +5 cm/s. Acceleration is positive, and constant (if the position vs. time curveis parabolic.) Initial position = 3 cm.E. Velocity and acceleration are both changing and alternating from positive to negative, initial position =10 cm, alternates from 15 cm to 5 cm.F. Starting from origin, nearly constant velocity of about +17 cm/s for the first second, then changes tonegative velocity. Acceleration changes from zero (first second), to negative, to positive (at about 2seconds). Object "disappears" or data is lost from 3 - 4 seconds.(D)* [em)(wa) x(mo) x

In graph J, object starts with initial velocity 3cm/s and then velocity is continuously decreasing.…

0. 15 14 time (3) tine (s) time (5) 3 1 3 time (s) 15 time (s) time (s) J. Constant acceleration = -1 cm/s, initial velocity +3 cm/s. K. Initial velocity = zero, acceleration is positive and increasing to about +1 cm/s/s. L. Initial velocity = zero. For first 2 seconds, acceleration = -2 cm/s, from 2-3 seconds, acceleration = +4 cm/s?; after t = 3 seconds, both velocity and acceleration are zero. M. Acceleration is initially negative, changes to zero. Initial velocity = 4 cm/s, decreases to about -1.5 cm/s. N. Initial velocity 4 cm/s. Acceleration is initially negative, changes to zero by 3 seconds and remains zero. Final constant velocity = +1.5 cm/s. O. Initial velocity = -2 cm/s, is constant for first 2 seconds. Then there is a constant acceleration of (om/s) (cmis) (syma) a v (om/s) ¥ (cm/s)

0. 15 14 time (3) tine (s) time (5) 3 1 3 time (s) 15 time (s) time (s) J. Constant acceleration = -1 cm/s, initial velocity +3 cm/s. K. Initial velocity = zero, acceleration is positive and increasing to about +1 cm/s/s. L. Initial velocity = zero. For first 2 seconds, acceleration = -2 cm/s, from 2-3 seconds, acceleration = +4 cm/s?; after t = 3 seconds, both velocity and acceleration are zero. M. Acceleration is initially negative, changes to zero. Initial velocity = 4 cm/s, decreases to about -1.5 cm/s. N. Initial velocity 4 cm/s. Acceleration is initially negative, changes to zero by 3 seconds and remains zero. Final constant velocity = +1.5 cm/s. O. Initial velocity = -2 cm/s, is constant for first 2 seconds. Then there is a constant acceleration of (om/s) (cmis) (syma) a v (om/s) ¥ (cm/s)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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1. For each of the following graphs, discuss with your team and think of a motion that would create the graph. Be sure that you can accurately describe the velocity and acceleration for each motion. 2. Your team will be assigned two motions. Write a detailed description of the motions, with enough detail so that someone can follow your instructions and recreate the graph. 20 15 10 time (s) A. Constant position = 5 cm from origin. Velocity = 0, acceleration = 0. B. Constant velocity = +2 cm/s, acceleration = 0, initial position = 5 cm. C. Constant velocity = -3 cm/s, acceleration 0, initial position = 20 cm. %3D 20 15 15 E 10 10 21 12 tim: (5) D. Velocity changes from 0 to +5 cm/s. Acceleration is positive, and constant (if the position vs. time curve is parabolic.) Initial position = 3 cm. E. Velocity and acceleration are both changing and alternating from positive to negative, initial position = 10 cm, alternates from 15 cm to 5 cm. F. Starting from origin, nearly constant velocity of…
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