. Consider a laboratory experiment in which three different chemicals were added to culti ourpose of the experiment was to compare the effects of the chemicals on the growth of the v he diameter of the affected area. The data given in the table below: A в 17.1 24.3 14.3 14.9 21.7 14.5 23.6 22.3 17.1 16.0 26.4 13.2 18.7 23.2 15.6 21.7 20.7 10.3 21.4 22.9 23.0 196
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- You have been hired to measure the concentration of ammonia in water from wells at two districts on Long Island. After sampling 10 wells in one of the districts you find the values are, in mg/L: 6.4, 2.1, 1.4, 0.7, 6.8, 3.2, 2.7, 1.6, 4.9, 1.2. Your assistant plots the data from the second set of wells and the histogram of data from that sample looks pretty much the same as for your data set. Which statistical test do you anticipate that you will use? An one-sample t-test An unpaired, two-sample t-test A paired, two-sample t-test A one-way anova A Mann-Whitney U test Main Contentassume that the data was obtained from two indepen-dent samples. That is, 28 subjects were enrolled into the study, and half were randomly assignedto the corn flakes diet, and half to the oat bran diet. After two weeks the LDL cholesterol level ofeach individual was recorded. LDL (mmol/l)Subject Corn Flakes Oat Bran1 4.61 3.842 6.42 5.573 5.40 5.854 4.54 4.805 3.98 3.686 3.82 2.967 5.01 4.418 4.34 3.729 3.80 3.4910 4.56 3.8411 5.35 5.2612 3.89 3.7313 2.25 1.8414 4.24 4.14 Questions; a) What are the appropriate null and alternative hypotheses for a two-sided test?(b) Conduct the test at the 0.05 level of significance. What is the p-value?(c) Construct a 95% confidence interval.After the detonation of a 20-kiloton nuclear bomb in China, scientists in Japan and the U.S. conducted tests to measure the radiation. The results are as follows; JAPAN .2 .4 .5 .1 .3 .3 U.S. .2 .3 .1 .1 .2 .2 4 .1 A. At a level of significance 0.10 decide whether fallout in Japan was significantly greater than fallout in the S. Also give the means and standard deviations for the two samples. State hypotheses, P-value and conclusion. B. Find a 80% confidence interval for these results. What does it seem to indicate?
- 18. We want to study the relationship between size (sq. m) and the price of houses. We randomly chose 25 houses and recorded the size and price of them. The excel output for the data is given below: Regression statistics: Multiple R: 0.586378154 R Square: 0.343839339 Adjusted R Square: 0.315310615 Standard Error: 34761.73162 Observations: 25 df SS MS F SignificanceF Regression 1 14563843876 1.46E+10 12.05239 0.0020659 Residual 23 27792693660 1.21E+09 Total 24 42356537536 Coefficients StandardError T stat P-value lower95% upper95% Lower95.0% upper95.0% Intercept 189769.0334 28557.61831 6.645128 8.85E-07 130693.1 248844.968 130693.1 248844.968 Size (sq.meter) 444.1951525 127.9490924 3.471655 0.002066 179.51229 708.878016 179.51229 708.878016 Write down your answers to (a)-(c) in the box below. Give your answers to 4 decimal places. Write down 95% confidence interval for the slope of the relationship between price and size. We want to…A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. Full data set Carpeted Uncarpeted 14.214.2 15.415.4 1616 6.46.4 6.76.7 7.97.9 9.79.7 8.38.3 7.57.5 8.38.3 12.412.4 11.911.9 9.99.9 13.613.6 9.59.5 7.67.6 Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the alpha equals 0.05α=0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. A. Upper H 0H0: mu 1 less than mu 2μ1<μ2 Upper H 1H1: mu 1 greater than mu 2μ1>μ2 B. Upper H 0H0: mu 1 equals mu 2μ1=μ2 Upper H 1H1: mu 1 greater than mu 2μ1>μ2 Your answer is…The average number of hours of relief provided by 5 different tablets are as follows: Tablet 1 Tablet 2 Tablet 3 Tablet 4 Tablet 5 5 9 3 2 7 4 7 3 6. 8. 8. 4 6. 6. 3 1 4 3 9. 7 4 T = 26 T, = 39 T = 20 T =14 T =33 %3D %3D NOTE: Ex =834 The ANOVA table shown below is partially completed with the information in the table above. The data is from five different tablets (independent populations) that are normally distributed with equal variances. Degrees of Freedom Sum of Squares Mean Square F Treatment 79.440 Error Total 24 a) Fill in the missing values and complete the ANOVA table. b) Using the information from the table above test whether there is a significant difference in the average number of hours of relief provided by the tablets differ for at least 2 of the brands. Use a = 0.05
- The blood lead concentrations, in micrograms per deciliter (µg/dL), of 20 children from two different neighborhoods were measured. The results are recorded in the table. Neighborhood 1 3.97 3.92 3.99 3.71 4.13 3.97 4.02 3.88 4.12 3.70 3.96 3.78 4.30 4.09 4.13 4.94 3.93 3.95 3.86 3.83 Neighborhood 2 4.32 4.23 3.78 4.10 4.35 4.21 4.36 4.21 4.02 4.05 4.29 4.12 4.59 4.12 4.02 3.85 3.97 4.28 4.39 4.14 Using the same scale, draw a box-and-whisker plot for each of the two data sets, placing the second plot below the first. Considering that high blood lead concentrations are harmful to humans, in which of the two neighborhoods would you prefer to live? neighborhood1 or neighborhood 2A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. Full data set Carpeted Uncarpeted 5.6 11.5 11.1 7.9 7.9 13.5 14 11.2 15.4 8.3 7.2 7.7 11.8 7.6 12.9 5.6 Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the a = 0.01 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. A. Ho: H1 =H2 H1: H1 > H2 B. Ho: H1 H2 O C. Ho: H1 = H2 H1: Hy # H2 O D. Ho: H1 = H2 H1: H1A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. Full data set O Uncarpeted 10.1 11.3 Carpeted 10.9 13.7 15.9 10.1 12.4 15.3 11.3 5.7 7.8 10.2 5.3 9.2 13.6 14 Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the a = 0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. O A. Ho: H1 = H2 O B. Ho: H1 = H2 H: H1 > H2 OC. Họ: H1 =H2 O D. Ho: H1A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. Full data set O Carpeted 10.9 13.7 10.1 12.4 15.3 Uncarpeted 15.9 10.2 10.1 11.3 11.3 5.7 5.3 7.8 13.6 9.2 Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the a= 0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. O A. Ho: H1 = H2 H: H1 H2 OC. Họ: H1 = H2 H: H1 H2 O D. Ho: H1A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. Full data set Carpeted Uncarpeted 7.5 14.9 9.4 5.1 10.6 4.2 9.2 12.7 9.9 13.3 9.3 4.2 6.9 11.1 7.5 12.5 Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the α=0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. A. H0: μ1=μ2 H1: μ1>μ2 This is the correct answer. B. H0: μ1<μ2 H1: μ1>μ2 C. H0: μ1=μ2 H1: μ1≠μ2 D. H0: μ1=μ2 H1: μ1<μ2 Your answer is not correct. Determine the P-value for this hypothesis test. P-value=nothing…The following data are from an experiment on carnations. The explanatory variable is the amount of inorganic bromine (micrograms per milliliter) in a plot of standard size. The response variable is the average number of flowers per carnation plant for the 30 plants grown in the plot. Find the change in number of flowers per plant given an increase in 1 µg per mL of inorganic bromine. Amount of bromine Average no. of flowers Select one: O a. -0.216 O b. 0.216 O c. O d. -3.81 4.04 3 3.2 4 2.9 6 3.7 7 2.2 8 1.8 10 2.3 12 1.7 15 16 0.8 0.3SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. 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