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Essay about Psy/315 Week 3- Individual Assignments

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Chapter 2 11. a) Mean is 2 b) Median is 2 c) Sum of square deviations is 56. d) Variance is 2.666 or 2.7 e) Standard deviation is 1.632 or 1.6 12. a) Mean is 1312.4 or 1312 b) Median is 1361 c) Sum of square deviations is 76092.2 d) Variance is 15218.44 e) Standard deviation is 123.363 13. a) Mean is 3.166 b) Median is 3.25 c) Sum of square deviations is 0.44738 d) Variance is 0.074 e) Standard deviation is 0.272 16. a) Governor-Mean is 43 and Standard deviation is 5.916 CEO- Mean is 44 and standard deviation is 10.954 b) In order to calculate the mean or average for the governors and CEO’s, I added together all the figures and divided that sum by 4 since there …show more content…

25. a) Probability that it is a student = 800 / 1000 = 0.80 or 80% b) Probability that it is a faculty member = 50 / 1000 = 0.05 or 5% c) Probability that it is an admin = 150 / 1000 = 0.15 or 15% d) Probability that it is a faculty or admin member = Probability that it is a faculty member + Probability that it is an admin member = 0.05 + 0.15= 0.20 or 20% e) Probability that it is anyone but an admin member = Probability that it is a student + Probability that it is a faculty member= 0.80 + 0.05 = 0.85 or 85%. f) To find the probability of each of these answers you would start by dividing the possible successful outcomes by the total number of possible outcomes. In the example E, the question asked for anyone except an administrator, therefore, taking the total amount of people minus the administrator will give you a category for those you want to have picked. After that, you would continue as if you had the successful possibilities divided by all possible

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