PS2 Semi Finished Essay

p2 + 2pq + q2 = 1 ; where ‘p2’ represents the homozygous dominant genotype, ‘2pq’ represents the heterozygous genotype, and ‘q2’ represents the homozygous recessive genotype

1) If the frequency of a recessive allele is 30% in a population of 100 people, how many would you predict would be carriers of this allele, but would not express the recessive phenotype?

GENETIC CROSSES An “X” is used to indicate that two individuals have been mated together. The parents are designated as P (for parental) and the offspring as F (for filial). When several generations are involved, subscripts are added to designate the generations. P1 give rise to F1 (first filial) progeny. If the F1 are crossed together they become P2 and their progeny F2. A cross between members of the F1 and members of the P1 is a backcross. A cross between members of the F1 and the true breeding recessive P1 is a test cross. MONOHYBRID CROSS The simplest form of a cross is a monohybrid cross, which analyses a single trait and its associated variations. The diagram below shows the

2. Can the student tell from the blood type if the student is heterozygous or homozygous? Explain. (5 points) Yes, knowing your blood type would

What observations can you make regarding the gene pool and gene frequency of the surviving individuals?

9. No, because each child's 2 sets of chromosomes are rearranged independently, so that there is an equal probability of all of them having the same genotype (1/2^4, or 1/16) as there is of them having all different ones

4. Clear wing, Black eye, and Hairless (c, b, and h) are linked, recessive traits carried on

b) How do the products of meiosis compare to the original cell? Think about chromosome number. (1 point)

Suppose the feather color of a bird is controlled by two alleles, D and d. The D allele results in dark feathers, while the d allele results in lighter feathers.

Once the Punnett square for Question 12 is complete, calculate the ratio of purple and yellow kernels (recall that if the dominant trait is present, it will be expressed).

2. How will the alleles for these traits assort into the gametes that each parent might produce? (Hint: For a reminder on how alleles sort independently into gametes, refer to the illustration in Part 2, Question 2, in the Student Guide.)

Now you have determined some facts about the grounded allele and the trait that it causes. Given what you know, do you expect the mutant F1 flies to be homozygous or heterozygous for the allele that causes the grounded trait? According to your reasoning, if you mated two mutant F1 flies, what percentage of flies would you expect to be wild type versus mutant in the F2 progeny? Draw a Punnett square of this cross to justify your answer.

Gathering Data on the Different Traits of the Garden Pea (Pisum Sativum), Organizing the Dominant/Recessive Phenotypes of 60 F2 Offspring and Determining Whether the Null Hypothesis is Rejected or Accepted Using the Chi-Square Test.

You are also provided with a heterozygous female, and a homozygous recessive male for a genetic cross. In this particular female, all the dominant alleles are on one chromosome, and the recessive counterparts are on the other homologous chromosome. Due to a chromosomal condition, in the female no recombination occurs between the M and N loci. Normal recombination occurs between the L and M loci. Diagram this cross, and show the genotypes and frequencies of all offspring expected from this cross.

Using the Hardy-Weinberg equation, calculate the predicted genotype frequencies for each population scenario below. Place your calculations and data in the space provided below. Once you have calculated the frequencies, answer the conclusion questions for each one. Please remember that all calculations must be shown for full credit.