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- (d) 3-13. Distis me Jum 4 A method of analysis yields weights for gold that are low by 0.4 mg. Calculate the caused by this uncertainty if the weight of gold in the sample is (a) 900 mg. (c) 150 mg. 1-7. The method described in Problem 3-6 is to be used for the analysis of ores that assay about 1.2% gold. What minimum sample weight should be taken if the relative error resulting from a 0.4-mg loss is not to exceed -0.2%? percent relative error (a) (b) (b) 600 mg. (d) 30 mg. 3-14. Wha stan stam 3-15. Сог mea (b) -0.5%? (a) -0.8%? (c) (d) 1.2%? 3.5 3-8. The color change of a chemical indicator requires an overtitration of 0.04 mL. Calculate the percent relative error if the total volume of titrant is (a) 50.00 mL. (c) 25.0 mL. 3-9. A loss of 0.4 mg of Zn occurs in the course of an analysis to determine that element. Calculate the per- cent relative error due to this loss if the weight of Zn in the sample is (a) 40 mg. (c) 400 mg. 3.1 3.1 (b) 10.0 mL. 3.3 2.5 (d) 40.0 mL. Fo (a (E (b) 175…Chemistry Common Isotopes and Mass spectrum of element Mo are given below Most common isotopes: Mo-98; Mo-96 Mo-95; Mo-92; Mo-97 ; Mo-100; Mo-94 Calculate the average atomic mass of Mo How the MS determined the relative intensity (Scale of 100) and Isotope abundance (%)? Why absolute intensity was not used? Can detector sensitivity, ICPMS temperature influence the relative intensity? ExplainArrange the following steps according to the order of process in Mass spectrometry Ion Separation Ionization Output/Data Result Detection
- To quantify the Cadmium content in a water sample, 5 aliquots of 10 mL were taken, adding to each one of them a volume of a standard solution of Cd (2 mg / mL); after the addition the final volume for all solutions was 50 mL. The absorbance reading was taken in an Atomic Absorption spectrophotometer, the data recorded were: Aliquot 1 2 3 4 5 Cd solution (mL) 0 1 2 3 4 Absorbance 0.163 0.240 0.319 0.402 0.478 Calculate the ppm of Cd.A 10.00-g sample containing an analyte was transferred to a 250-mL volumetric flask and diluted to volume. When a 10.00-mL aliquot of the resulting solution was diluted to 25.00 mL it was found to give a signal of o.235 (arbitrary units). A second 10.00-mL aliquot was spiked with 10.00 mL of a 1.00- ppm standard solution of the analyte and diluted to 25.0o mL. The signal for the spiked sample was found to be o.502. Calculate the weight percent of analyte in the original sample.Which atomic spectrometer has the highest atomization temperature? What is the advantage of having such a higher atomization temperature?
- Exactly 5.00 mL aliquots of a solution containing analyte X were transferred into 50.00-mL volumetric flasks and the pH of the solution is adjusted to 9.0. The following volumes of a standard solution containing 2.00 µg/mL of X were then added into each flask and the mixture was diluted to volume: 0.000, 0.500, 1.00, 1.50 and 2.00 mL. The fluorescence of each of these solutions was measured with a fluorometer, and the following values were obtained: 3.26, 4.80, 6.42, 8.02 and 9.56, respectively. ii. Using relevant functions in Excel, derive a least-squares equation for the data, and use the parameters of this equation to find the concentration of the phenobarbital in the unknown solution.1FbhGb6cd_1-5c/IV_Ivqu J4002epq/z4kbhpYZSIA opy ✩✩ IS Extensions Help I text Calibri. 12 +BIU A d f5 A % 5 T f6 1 5 J 1. Why is it recommended to have a carbon monoxide detector on each floor of a home? Page 4: Water Pollution: Questions i M 6 2. What impact would the increased use of electric vehicles have on environmental damage caused by acid rain? Page 3: More Air Pollution Issues: Questions 4. The COVID-19 pandemic forced many people to work from home for extended periods. During these periods, many cities reported unusually low levels of smog. Suggest an explanation for this observation. 5. Explain how ozone can be both harmful and beneficial. 3. Why is ground level ozone most likely to reach its highest concentrations on hot, sunny days during periods of heavy traffic in large cities? f7 Y []») 3 6. India relies heavily on burning coal to generate electricity. How does India's reliance on coal contribute to the poor air quality experienced in many of India's major cities? & 7 18…Name: Intensity 80 1s 70 Peak X 8 7 Due: Wed., 3/1/23 Peak Y Page 2 / 9 40 Binding Energy (MJ/mol) D t 8 I 2 2. A sample containing atoms of C and F was analyzed using x-ray photoelectron spectroscopy. The portion of the spectrum showing the Is peaks for atoms of the two elements is shown above. Which of the following correctly identifies the 1s peak for the F atoms and provides an appropriate explanation? (A) Peak X, because F has a smaller first ionization energ than C has. (B) Peak X, because F has a greater nuclear charge than C has. (C) Peak Y, because F is more electronegative that C is. (D) Peak Y, because F has a smaller atomic radius that C has. + 0 AP Chemistry Sign out
- Question 19 of 27 > Graphs are a common data analysis tool used in all branches of science. The given graph represents how light absorbance at 423 nm varies with concentration of an organic dye. Identify the parts of the graph. Answer Bank y = 0.210x – 0.032 line equation Title Abs423 Dye Conc. (nM) best-fit line 0 i 2 3 4 5 6 7 8 9 10A 10.00 g sample containing an analyte was transferred to a 250 mL volumetric flask and diluted to volume. When a 10.00 mL aliquot of the resulting solution was diluted to 25.00 mL it was found to give a signal of 0.235 (arbitrary units). A second 10.00 mL aliquot was spiked with 10.00 mL of a 1.00 ppm standard solution of the analyte and diluted to 25.00 mL. The signal for the spiked sample was found to be 0.502. Calculate the weight percent of analyte in the original sample.(b) A compound having molecular weight 151.163 g/mol is determined in a sample. A 0.0302 g sample was dissolved in an aqueous solvent and diluted the solution to 1 L. The solution has A max at 243 nm (ɛ=2.6×104 cm1 mol1 L). The solution exhibits an absorbance of 0.642 in a 2 cm cell. Calculate the percentage of the above compound in the sample.