Torques, cross product, and the “right-hand-rule” The figure below shows three forces acting on a rigid body. L 293 F3 45° 25 cm direction of 7₁=₁ × Ē • direction of 72 = √₂ x F₂ • direction of 73 = T3 × F3 F₁ = 5N 30 cm 20 cm 60° F₂ = 2N First, use the right-hand-rule to find the directions of the torques, 71, 72, and 73 about point O? The direction k points out of the page. Next, calculate the torques to find F3 so that there is no net torque: 7₁ +72+73=0

Principles of Physics: A Calculus-Based Text
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Chapter10: Rotational Motion
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Torques, cross product, and the “right-hand-rule”
The figure below shows three forces acting on a rigid body.
L
293
F3
45°
25 cm
direction of 7₁=₁ × Ē
• direction of 72 = √₂ x F₂
• direction of 73 = T3 × F3
F₁ = 5N
30 cm
20 cm
60°
F₂ = 2N
First, use the right-hand-rule to find the directions of the torques, 71, 72, and 73 about
point O? The direction k points out of the page.
Next, calculate the torques to find F3 so that there is no net torque:
7₁ +72+73=0
Transcribed Image Text:Torques, cross product, and the “right-hand-rule” The figure below shows three forces acting on a rigid body. L 293 F3 45° 25 cm direction of 7₁=₁ × Ē • direction of 72 = √₂ x F₂ • direction of 73 = T3 × F3 F₁ = 5N 30 cm 20 cm 60° F₂ = 2N First, use the right-hand-rule to find the directions of the torques, 71, 72, and 73 about point O? The direction k points out of the page. Next, calculate the torques to find F3 so that there is no net torque: 7₁ +72+73=0
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