THIS IS A SIMPLE BEAM WITH A SPAN LENGTH, L = 5M, BUT WITH 2M OVERHANG AT BOTH ENDS. 15KN 2M 2M 3M 2M 5M R, R2 1. DRAW THE INFLUENCE LINES ALONG WITH; A.) ALL SUPPORT REACTIONS, B.) MOMENT AT 0.4L FROM THE LEFT SUPPORT C.) SHEAR AT 0.4L FROM THE LEFT SUPPORT

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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THIS IS A SIMPLE BEAM WITH A SPAN LENGTH, L = 5M, BUT WITH 2M
OVERHANG AT BOTH ENDS.
15KN
2M
2M
3M
2M
5M
Ř,
R2
1. DRAW THE INFLUENCE LINES ALONG WITH;
A.) ALL SUPPORT REACTIONS,
B.) MOMENT AT 0.4L FROM THE LEFT SUPPORT
C.) SHEAR AT 0.4L FROM THE LEFT SUPPORT
2. AFTER DRAWING THE INFLUENCE DIAGRAMS
LOCATE AND SOLVE FOR THE FOLLOWING;
A.) SINGLE CONCENTRATED LOAD OF 15KN
B.) UNIFORM LOAD OF 15KN/M WITH A 2.5 LOADED LENGTH
Transcribed Image Text:THIS IS A SIMPLE BEAM WITH A SPAN LENGTH, L = 5M, BUT WITH 2M OVERHANG AT BOTH ENDS. 15KN 2M 2M 3M 2M 5M Ř, R2 1. DRAW THE INFLUENCE LINES ALONG WITH; A.) ALL SUPPORT REACTIONS, B.) MOMENT AT 0.4L FROM THE LEFT SUPPORT C.) SHEAR AT 0.4L FROM THE LEFT SUPPORT 2. AFTER DRAWING THE INFLUENCE DIAGRAMS LOCATE AND SOLVE FOR THE FOLLOWING; A.) SINGLE CONCENTRATED LOAD OF 15KN B.) UNIFORM LOAD OF 15KN/M WITH A 2.5 LOADED LENGTH
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