The rate law for the mechanism below is Iz0 = 21o K1, fast ln+ CO = COI K2, fast COLO + Io - COL2o k3, slow O rate = K,0.5 k3 [cOI][1]0.5 %3D rate K2k3[CO][1]² %3D rate = k3[COI][I] %3D rate = K0.5 K2k3 [CO][12]0.5[1] O rate K K2k3 [CO][12]

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter12: Kinetics
Section: Chapter Questions
Problem 36E: From the given data, use a graphical method to determine the order and rate constant of the...
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Question 5
The rate law for the mechanism below is
Ize = 21 K1, fast
l + CO = COL K2, fast
COLO + In
COL2e k3, slow
O rate = K0.5 k3 [co][L]05
%3D
rate = K2k3[CO][1]²
rate = k3[COI][1]
rate K0.5 K2k3 [COJ[12]0.S[1]
%3D
rate = K, K2k3 (CO][12]
%3D
Transcribed Image Text:Question 5 The rate law for the mechanism below is Ize = 21 K1, fast l + CO = COL K2, fast COLO + In COL2e k3, slow O rate = K0.5 k3 [co][L]05 %3D rate = K2k3[CO][1]² rate = k3[COI][1] rate K0.5 K2k3 [COJ[12]0.S[1] %3D rate = K, K2k3 (CO][12] %3D
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