The formula for the braking distance of a car is: 0.03361v² μ d= where: .d is the braking distance (in feet) ● v is the initial velocity of the car (in miles per hour) is the coefficient of friction between the tires and the roadway At the scene of an accident, the driver tells a police officer he had been driving at 25 miles per hour when he slammed on his brakes and skidded off the road. If the road is covered in snow with a friction coefficient of μ = 0.25, how long should the skid marks be if the driver was really going 25 miles per hour? feet (Round to 1 decimal place.) The officer measures the skid marks and finds they are 147 feet long, which shows the driver was going faster than 25 miles per hour. Use d = 147 to determine the actual speed of the car. d=

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Chapter1: Units And Measurement
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Problem 33P: In SI units, speeds are measured in meters per second (m/s). But, depending on where you live,...
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The formula for the braking distance of a car is:
0.033612²
μ
d=
where:
.d
v
●
is the braking distance (in feet)
is the initial velocity of the car (in miles per hour)
is the coefficient of friction between the tires and the roadway
At the scene of an accident, the driver tells a police officer he had been driving at 25 miles per hour when he
slammed on his brakes and skidded off the road.
If the road is covered in snow with a friction coefficient of μ = 0.25, how long should the skid marks be if the
driver was really going 25 miles per hour?
feet (Round to 1 decimal place.)
d=
The officer measures the skid marks and finds they are 147 feet long, which shows the driver was going faster
than 25 miles per hour. Use d = 147 to determine the actual speed of the car.
miles per hour (Round to 1 decimal place.)
V=
Transcribed Image Text:The formula for the braking distance of a car is: 0.033612² μ d= where: .d v ● is the braking distance (in feet) is the initial velocity of the car (in miles per hour) is the coefficient of friction between the tires and the roadway At the scene of an accident, the driver tells a police officer he had been driving at 25 miles per hour when he slammed on his brakes and skidded off the road. If the road is covered in snow with a friction coefficient of μ = 0.25, how long should the skid marks be if the driver was really going 25 miles per hour? feet (Round to 1 decimal place.) d= The officer measures the skid marks and finds they are 147 feet long, which shows the driver was going faster than 25 miles per hour. Use d = 147 to determine the actual speed of the car. miles per hour (Round to 1 decimal place.) V=
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