Te = 96 °CT₁=T₁ = 10T₂ = 0P = 49.8 barCriticalpointEnter the temperature in C for state 3.P₁ = 6 barP₂ = 4.5 barProcess 1-2 Pv" = C & n = 1.054Process 2-3 isobaricProcess 3-4: volume remain constantSubstance: Find the substance withcritical propertiesm = 5 kg

Pc=49.8 bar Tc=96oc=369 k P3=P2=4.5 bar T4=10oc To find : The temperature, T3.

Te = 96 °C T₁=T₁ = 10 T₂ = 0 Pe=49.8 bar Critical point Enter the temperature in C for state 3. P₁ = 6 bar P₂ = 4.5 bar Process 1-2 Pu" = C & n = 1.054 Process 2-3 isobaric Process 3-4: volume remain constant Substance: Find the substance with critical properties m = 5 kg

Te = 96 °C T₁=T₁ = 10 T₂ = 0 Pe=49.8 bar Critical point Enter the temperature in C for state 3. P₁ = 6 bar P₂ = 4.5 bar Process 1-2 Pu" = C & n = 1.054 Process 2-3 isobaric Process 3-4: volume remain constant Substance: Find the substance with critical properties m = 5 kg

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Pipeline with gas at 20 bar Chamber A 1.5 kg valve Chamber B Total volume = 1.25 m³ An insulated tank is fitted with a freely-floating piston made of a non-conducting material as shown in Figure. The pressure in the two chambers must always be the same at any specific time (PA=PB). The chambers are insulated from each other as well as from the environment. To the left of the piston (chamber A) is 1.5 kg of steam, initially at 4 bar and 90% quality. To the right of the piston (chamber B) is air, initially at 25° C and 4 bar. The total volume of the steam and air is 1.25 m³. Additional air from a pipeline is forced into the right side of the cylinder which forces the piston to move to the left, increasing the steam pressure. The air in the pipeline is at 20 bar. The valve is closed, and the air flow is stopped when no more liquid remains in the left chamber. When the valve is closed, PA = PB = 15 bar and the temperature in the right chamber is 115°C. Model the air as an ideal gas with…
(Q5] (a) The chamber contains 0.05 m' of ideal gas at a pressure of 20 KPa. The gas is subjected to an isothermal compression. until pressure reaches to 30 KPa. After that the gas is subjected to compression according to PV 2-const until pressure reaches to 40 KPa then an isobaric compression is done till volume reaches 0.005 m3. Assume that no loss in gas during the whole process : I- Sketch the process on P-V diagram and P-T diagram II- Find the work done during the entire process and temperature at end of each process.. gas
We give: AB: adiabatic trigger such as VB = 2 VA AC: isothermal compression PA =1bar=105 Pa , VA = 10^-2 m3 Gas temperature at point A: TA= 300 Kelvin Perfect gas constant: R = 8,31 J.mol-1.K-1 Molar thermal capacity at constant pressure:Cp = 29 J.mol-1.K-1 Calorific capacity ratio of this gas: Cp/Cv = 1,40 4 – Calculate the amount of QBC heat and WBC work received by the system for the transformation that changes the system from state B to state C.5 – a – Why is the UCA internal energy variation of the gas zero during the CA transformation? b – Apply the first principle to the ABCA cycle and deduce the WAB work received by the gas during theadiabatic relaxation AB.c – Interpret the WAB sign.
Derivation of the Bernoulli’s equation based on Mechanical Energy Balance
|Q4:0 Skg of Steam at pressure of 4.9 bar is produ- ced from uwater at 20%. Determine the amount 0.9 dry. [12263 leg] of heat supplied it the Steam is to o
Consider an experimental structure required to always have constant pressure. For this purpose, a collapsible compartment has been installed that expands and contracts to adjust the volume of air inside the structure for maintaining constant air pressure of 1 atm. Given the total volume of air inside the structure was 100,000 m' when the compartment was fully collapsed, solve the following: If a constant pressure is to be maintained while the temperature varies from 0°F to 150°F, find the volume of air that the compartment holds when it expands to the maximum. For the temperature transition mentioned above, find the change in internal energy undergone by the air in the structure. Also, find the work done by the compartment while it expands. Assume air to be an ideal gas.
First study the material presented in the class, Second have a look on how to use the thermodynamic tables where I have some notes in it, and Third watch this or any similar videos (https://www.youtube.com/watch?v=FapSjWERCY4) on how to use thermodynamic tables to find the properties. Q1. Complete this table for H,O: T, °C Р, КРа u, kJ/kg Phase description 400 1450 220 Saturated vapor 190 2500 4000 3040 Q2. Complete this table for H2O: T, °C Р, КРа v, m³/kg Phase description 50 7.72 400 Saturated vapor 250 500 350 110 Q3. Complete this table for H2O: T, °C Р. КРа v, m³/kg Phase description 140 0.05 550 Saturated liquid 125 750 500 0.140
Constants I Periodic Table A cylindrical pipe has inner radius R1 and outer radius R2 . The interior of the pipe carries hot water at temperature T1. The temperature outside is T, (< T1). Suppose the pipe is steel with R1 of its temperature? = 3.3 cm , R2 = 4.2 cm , and T2 = 18 °C. If the pipe holds still water at Ti = 70 ° C, what will be the initial rate of change Express your answer using two significant figures. Πν ΑΣφ dT °C/s dt Previous Answers Request Answer Submit X Incorrect; Try Again; 8 attempts remaining Part C Suppose water at 70 °C enters the pipe and moves at a speed of 8.4 cm/s . What will be its temperature drop per centimeter of travel? Express your answer using two significant figures. nνα ΑΣφ dT °C/cm dx Request Answer Submit
m 이 D Pi D h
Find the pressure difference between points A and B. (1,3,5,7,9): Liquid is Chloride with density 1490 kg/m³ and H = 25 cm. Liquid Oil (sg = 0.90) %3D 12 A cm 16 H 12 cm cm cm cm Mercury (sg = 13.54)
Q2: Consider a cylinder with mass m and radius r submerged partially or totally in a liquid of weight density p. Derive the differential equation that express the displacement of the water and find its solution if at t-0,(x = 0.2 m. Positive a-direction Equilibrium state Fquilibrium position x-0 Waler line 中

A:YV 36 ll 46.ll Test 3.pdf F1 F2 a F3 A d. C a F4 E Consider the following values: - F5 a = 12 m; b = 10 m; c = 10 m; d = 8 m; F1 = 6 kN; F2 = 7 kN; F3 = 8 kN; F4 = 9 kN; F5 = 10 kN; a = 30° 0 = 45° B = 60° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 111.6 kN.m b) 112.6 kN.m c) - 184.6 kN.m d) - 109.6 kN.m e) - 104.1 kN.m f) None of them 2] What is the resultant moment of the five forces acting on the rod about point B? a) -95.8 kN.m b) 42.7 kN.m c) 80.9 kN.m d) 10.9 kN.m e) 51.8 kN.m f) None of them 3] What is the resultant moment of the five forces acting on the rod about point C? a) 32.6 kN.m b) - 21.1 kN.m c) 17.4 kN.m d) - 16.5 kN.m e) 15.6 kN.m f) None of them 4] What is the resultant moment of the five forces acting on the rod about point D? a) 37.6 kN.m b) 73.8 kN.m c) 71.6 kN.m d) 52.1 kN.m e) 21.1 kN.m f) None of them 5] What is the moment of the force F2 about point E? a) 90.7 kN.m b) - 88.1 kN.m c) 54.6 kN.m d) 103.1 kN.m e)…