STARTING AMOUNTXDetermine the quantity of moles in 4.21 x 10²³ molecules of CaCl₂ADD FACTORx( )6.99110.98mol CaCl₂0.69977.64.21 x 10²3g CaCl₂ANSWER3.79 × 10²16.022 × 10²31g CaCl₂/mol molecules CaCl₂RESET375.53

Answered: Image /qna-images/answer/868808aa-46e8-43f0-8029-00f9dc69c23c.jpg

STARTING AMOUNT X Determine the quantity of moles in 4.21 x 1023 molecules of CaCl ADD FACTOR x( ) 6.99 110.98 mol CaCl 0.699 77.6 4.21 x 1023 ANSWER 3.79 x 10²1 6.022 x 1023 1 g CaCl₂ g CaCl₂/mol molecules CaCl₂ RESET 5 75.53

STARTING AMOUNT X Determine the quantity of moles in 4.21 x 1023 molecules of CaCl ADD FACTOR x( ) 6.99 110.98 mol CaCl 0.699 77.6 4.21 x 1023 ANSWER 3.79 x 10²1 6.022 x 1023 1 g CaCl₂ g CaCl₂/mol molecules CaCl₂ RESET 5 75.53

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter3: Equation, The Mole, And Chemical Formulas

Section: Chapter Questions

Problem 3.56QE

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

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STARTING AMOUNT
X
Determine the quantity of moles in 4.21 x 10²³ molecules of CaCl₂
ADD FACTOR
x( )
6.99
110.98
mol CaCl₂
0.699
77.6
4.21 x 10²3
g CaCl₂
ANSWER
3.79 × 10²1
6.022 × 10²3
1
g CaCl₂/mol molecules CaCl₂
RESET
3
75.53

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