V. Interest and depreciation is 11% in any scenario. Level-V: (System Integration and Efficiency) Ensure that the proposed power factor correction methods integrate seamlessly with the existing feeder system. Aim to improve overall system efficiency while meeting cost constraints and reliability requirements of the distribution network. Deliverables & Instructions: The students should submit a comprehensive design report that includes: 1) Design of solution with working functionality at each level of design to correct the overall power factor at peak load to 98% Power factor. 2) Design of solution to meet the anticipated increase in peak load that is almost 04% in summer Peak. 3) Complete Cost analysis in terms of designed solution to be most Economical / cost effective having resulting additional savings in kilowatt losses and in dollars per year when all capacitors are applied. Problem Title: Feeder Analysis, Optimization and System Design for Power Factor Correction. Problem Description: You are tasked with analyzing and optimizing 2.4/4.16-kV wye-connected feeder system of a power distribution network to improve power factor and efficiency. The feeder serves various loads including peak, synchronous motor, and daily minimum loads. The goal is to minimize costs associated with power factor correction while ensuring reliable operation. The different analysis and optimization levels that you will investigate are as follows: Level-I: (Feeder Impedance Analysis) Analyze the impedance characteristics of the feeder, considering its configuration and total impedance (0.50 + j1.3502). Evaluate how this impedance affects power delivery to different loads along the feeder. Level-ll: (Load Characterization) Characterize the various loads connected to the feeder. Feeder having peak load of 300A at a lagging Power factor of 0.7 for 1200 hours a year, synchronous motor of 500hp having efficiency of 78% and connected in parallel with 450kw at 0.7 Power factor lagging, Mechanical load on the motor including losses is 100kw for 4500 hours a year and minimum daily loads of approximately 135 A at 0.62 Power factor for 2800 hours a year. Understand their power requirements, power factors, and operating durations throughout the year. Level-III: (Power Factor Correction Strategies) Investigate strategies to correct the overall power factor of the feeder, particularly during peak load conditions. Explore various methods to achieve the target power factor of 0.98 lagging efficiently. Level-IV: (Cost Analysis and Optimization) Conduct a detailed cost analysis in terms of different methods of Power Factor Correction considering below given cost considerations. i. Average fixed charge rate is $0.20/KW ii. Average demand cost is $250/kW iii. iv. Energy cost is $0.045/kWh The annual cost of phase advancing plant is $4.75/kvar and that of erecting an extra generating plant and the required accessories is $4.2/KVA.

V. Interest and depreciation is 11% in any scenario. Level-V: (System Integration and Efficiency) Ensure that the proposed power factor correction methods integrate seamlessly with the existing feeder system. Aim to improve overall system efficiency while meeting cost constraints and reliability requirements of the distribution network. Deliverables & Instructions: The students should submit a comprehensive design report that includes: 1) Design of solution with working functionality at each level of design to correct the overall power factor at peak load to 98% Power factor. 2) Design of solution to meet the anticipated increase in peak load that is almost 04% in summer Peak. 3) Complete Cost analysis in terms of designed solution to be most Economical / cost effective having resulting additional savings in kilowatt losses and in dollars per year when all capacitors are applied. Problem Title: Feeder Analysis, Optimization and System Design for Power Factor Correction. Problem Description: You are tasked with analyzing and optimizing 2.4/4.16-kV wye-connected feeder system of a power distribution network to improve power factor and efficiency. The feeder serves various loads including peak, synchronous motor, and daily minimum loads. The goal is to minimize costs associated with power factor correction while ensuring reliable operation. The different analysis and optimization levels that you will investigate are as follows: Level-I: (Feeder Impedance Analysis) Analyze the impedance characteristics of the feeder, considering its configuration and total impedance (0.50 + j1.3502). Evaluate how this impedance affects power delivery to different loads along the feeder. Level-ll: (Load Characterization) Characterize the various loads connected to the feeder. Feeder having peak load of 300A at a lagging Power factor of 0.7 for 1200 hours a year, synchronous motor of 500hp having efficiency of 78% and connected in parallel with 450kw at 0.7 Power factor lagging, Mechanical load on the motor including losses is 100kw for 4500 hours a year and minimum daily loads of approximately 135 A at 0.62 Power factor for 2800 hours a year. Understand their power requirements, power factors, and operating durations throughout the year. Level-III: (Power Factor Correction Strategies) Investigate strategies to correct the overall power factor of the feeder, particularly during peak load conditions. Explore various methods to achieve the target power factor of 0.98 lagging efficiently. Level-IV: (Cost Analysis and Optimization) Conduct a detailed cost analysis in terms of different methods of Power Factor Correction considering below given cost considerations. i. Average fixed charge rate is $0.20/KW ii. Average demand cost is $250/kW iii. iv. Energy cost is $0.045/kWh The annual cost of phase advancing plant is $4.75/kvar and that of erecting an extra generating plant and the required accessories is $4.2/KVA.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.48P: With the same transformer banks as in Problem 3.47, Figure 3.41 shows the oneline diagram of a...

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