Problem Statement Based on Problem 5-22 from the textbook. if the intensity of the distributed load acting on the beam is w, determine the reactions at the roller A and pin B. W=3.9 kN/m a=2.3 m b=5.0m Theta 30 degrees A W
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- Repeat Problem 11.2-3 assuming that R= 10 kN · m/rad and L = 2 m.Problem Statement Based on Problem 5-22 from the textbook. if the intensity of the distributed load acting on the beam is w, determine the reactions at the roller A and pin B. w=2.5 KM/m 2=35* a= 9.3 m b=4.3 m 0 b W B1. A tripod shawn supports of note that ball and rocket joints are used to mount the tripuod a load P=1000N at point A. Take at points B,D, and C. consider the t LI L 2 L2: 4 L3 : 3 A : 45° g :30° %3D on x-z plane L2 POINT C (2,-2,3) C0,0,0) ミー- Determine the ff Force of AB - N Force of AC - N Force of AD : N
- The system shown in the figure has a weight of 1759 N whose weight acts at point G shown in the figure. Determine The Vertical Component Ay Acting On The Pin At A. Do not use negative numbers in the answer.In the given figure, support A is a roller and support B is a pin support. If P=15 kips, calculate the 1) vertical reaction at A, 2) vertical reaction at B, 3) horizontal reaction at B P 6 kips 6 kips В 6 ft – 3 ft 2 ft ' 2 ftThe figure shows a mechanical model of the Russel fracture traction device and the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The total weight of the leg and the cast is W=200 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=10 cm . Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A ( 3L/4= 75 cm) . The angle that cable 2 makes with the horizontal is measured as β=40 ° . Accordingly, in order for the leg to remain in balance in the position shown; a) Find the tensile force T 1 in cable 1 . (Write your result in N ) b) Find the tensile force T 2 in cable 2 . (Write your result in N ) c) Find the angle α of cable 1 with the horizontal
- The pipe is pulled by three cables as shown on the figure below. All three cables are subjected to known forces. Another cable is planned to be added on the system. This additional cable is designed to pull the pipe along the positive y-axis. The proposed cable, Fy is twice as much as the only force which tends to pull the pipe below the x-axis. (Fa= 7.5kN; Fb= 1.25kN; Fc=5kN) Find the summation of forces in x axis and y axis.The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and the cast is W=210 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=6 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=33°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) b) Find the tensile force T2 in cable 2. (Write your result in N) c) Find the angle α of cable 1 with the horizontal.PROBLEM 4: Find the reaction force components at point A and B. The member AB has a length of L=10m. The infinitesimal loads at point A and B are 1200N/m and 800N/m respectively. 12=5mm 1200 N/m/ A In L=10m 4₁=5m 0:38 800 N/m
- The simply supported beam is subjected to the loads as described in the figure and parameter table. Neglecting the thickness of the beam, calculate the horizontal and vertical support reactions at A and B. F A B C -4*- L3 parameter value units L1 L2 L3 ft 4 ft 6 ft theta 65 F 200 lb M 500 lb-ft For the answers, take to the right and up to be the positive directions. The support reaction at A in the z direction is NAz- lb The support reaction at A in the y direction is NAy- lb The support reaction at Bin the z direction is NB= lb The support reaction at Bin the y direction is NBy= lbSelect F1=108 and F2=112 on the train bridge in the figure. Find the force on the bar BC and whether it is the pull.Problem Statement Based on Problem 5-22 from the textbook. if the intensity of the distributed load acting on the beam is w, determine the reactions at the roller A and pin B. W=2.6 kN/m a=2.4 m b=4.8 m Theta 25 degrees A W ming B