Planet A is located 1.81 x 10^10 [m] away from its parent star. What is the radial acceleration of Planet A if it revolves around its parent star at a constant angular speed of 3.97 x 10-6 [rad/s] along a circular orbit?
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Planet A is located 1.81 x 10^10 [m] away from its parent star. What is the radial acceleration of Planet A if it revolves around its parent star at a constant angular speed of 3.97 x 10-6 [rad/s] along a circular orbit?
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- What is the radial acceleration (m/s) of mercury if orbital period is 88 days and orbit radius is 5.79x10^7What is radial Acceleration?In a distant star system there are many inhabitable planets. One of these planets is named Qomar. Qomar is 3.2 AU's from its star and takes 6.5 Earth years to go around its star once. There is another planet in the same star system called Ferenginar. Ferenginar is 0.9 AUs from the star. What is the length of a Ferengi year (on Ferenginar) in terms of Earth years?
- Neptune orbits the Sun with an orbital radius of 4.495 x 10^12 m. If the earth to sun distance 1A.U. = 1.5 x 10^11 m, a) Determine how many A.U.'s is Neptune's orbital radius (Round to the nearest tenth). b) Given the Sun's mass is 1.99 x10^30 kg, use Newton's modified version of Kepler's formula T^2 = (4pi^2/Gm(star)) x d^3 to find the period in seconds using scientific notation. (Round to the nearest thousandth). C) Convert the period in part b) to years (Round to the nearest tenth)A planet of mass m= 8.45 x 1024 kg is orbiting in a circular path a star of mass M= 6.95 x 1029 kg. The radius of the orbit is R= 3.15 x 107km. What is the orbital pperiod (in Earth days) of the planet Pplanet? Express your answer to three significant figures. Pplanet = ? daysThe Earth is 93 million miles (mi) from the Sun and its period of revolution is 1 year = 31,500,000 s. What is the radial acceleration of the Earth in its orbit about the Sun? Choose 0.0093 mi/s^2 18.6 mi/s^2 0.0000037 mi/s^2 0.0000136 mi/s^2
- A planet of mass 5.8 x 1024 kg orbits a star of mass 1.6 x 1030 kg in a circular orbit 10 x 1011 m from its center. Calculate the period of the orbit, in Earth years. Use G = 6.7 x 10-11 N m2/ kg2 and that one Earth year is 3.15 x 107 s. (Please answer to the fourth decimal place - i.e 14.3225)(a) Jupiter's third-largest natural satellite, Io, follows an orbit with a semimajor axis of 422,000 km (4.22 ✕ 105 km) and a period of 1.77 Earth days (PIo = 1.77 d). To use Kepler's Third Law, we first must convert Io's orbital semimajor axis to astronomical units. One AU equals 150 million km (1 AU = 1.50 ✕ 108 km). Convert Io's a value to AU and record the result. aIo = AU (b) One Earth year is about 365 days. Convert Io's orbital period to Earth years and record the result. PIo = yr (c) Use the Kepler's Third Law Calculator to calculate Jupiter's mass in solar units. Record the result. MJup(Io) = MSun (d) Based on this result, Jupiter's mass is about that of the Sun. Jupiter has a similar fraction of the Sun's volume. The two objects therefore have rather similar density! In fact, Jupiter has a fairly similar composition as well: most of its mass is in the form of hydrogen and helium.Astronomical observations of our Milky Way galaxy indicate that it has a mass of about 8 ✕ 1011 solar masses. A star orbiting near the galaxy's periphery is 6.0 ✕ 104 light years from its center. What should the orbital period (in y) of that star be?
- Two planets X and Y travel counterclockwise in circular orbits about a star as shown in Figure P11.14. The radii of their orbits are in the ratio 3:1. At one moment, they are aligned as shown in Figure P11.14a, making a straight line with the star. During the next five years, the angular displacement of planet X is 90.0 as shown in Figure P11.14b. What is the angular displacement of planet Y at this moment?Neptune orbits the Sun with an orbital radius of 4.495 x 10^12 m. If the earth to sun distance 1 A.U. = 1.5 x 10^11 m, a) Determine how many A.U.'s is Neptune's orbital radius (Round to the nearest tenth). b) Given the Sun's mass is 1.99 x 10^30 kg , use Newton's modified version of Kepler's formula T^2 = (4pi^2/Gm(star)) x d^3 to find the period in seconds using scientific notation. (Round to the nearest thousandth). c) Convert the period in part b) to years(Round to the nearest tenth).Sam is an astronomer on planet Hua, which orbits the distant star Barnard. It has recently been accepted that Hua is spherical in shape, although its exact size is unknown. While studying in the library, in the city of Joy, Sam learns that during equinox, Barnard is directly overhead in the city of Bar, located 1500.0 km north of his location. On the equinox, Sam goes outside and measures the altitude of Barnard at 83 degrees. What is the radius of Hua in km?