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- 80mL of a 0.3M solution of hexapeptide Leu-His-Cys-Glu-Asn-Arg is adjusted to pH=pI. The solution is then titrated with 0.2M HCL to a final pH of 2.1. Sketch the titration curve, labelling the pH and volume axes. Indicate the volume of HCL needed to reach relevant pKa value and equivalence point(s)z Relevant pKa values are: 2.1, 4.3, 6.0, 8.3, 9.8, and 12.5.80mL of a 0.3M solution of hexapeptide Leu-His-Cys-Glu-Asn-Arg is adjusted to pH=pl. The solution is then titrated with 0.2M HCI to a final pH of 2.1. Sketch the titration curve, labelling the pH and volume axes. Indicate the volume of HCl needed to reach each relevant pKa value and equivalence point(s). Relevant pka values are: 2.1, 4.3, 6.0, 8.3, 9.8, and 12.5.Tirofiban (C22H36N₂O5S MWt = 440.6) is present as tirofiban HCI monohydrate (C22H36N2O5S.HCI.H₂O MWt=495.1) at 0.281 mg/mL in a concentrated solution. A solution for infusion is prepared by extracting 50 mL from a 250 mL bag of 5% glucose solution and adding 50 mL of concentrated solution. Sofia who weighs weighs 87 kg requires a tirofiban dose of 0.1 mcg/kg/min for 12 to 24 hours. What would the infusion rate be (mL/h)? (Answer to 1 decimal place.) Answer:
- Tirofiban (C22H36N2O5S MWt = 440.6) is present as tirofiban HCI monohydrate MWt=495.1) at 0.281 mg/mL in a concentrated solution. (C22H36N2O5S.HCI.H₂O A solution for infusion is prepared by extracting 50 mL from a 250 mL bag of 5% glucose solution and adding 50 mL of concentrated solution. Sofia who weighs weighs 87 kg requires a tirofiban dose of 0.1 mcg/kg/min for 12 to 24 hours. What would the infusion rate be (mL/h)? (Answer to 1 decimal place.)Tirofiban (C22H36N₂O5S MWt = 440.6) is present as tirofiban HCI monohydrate MWt=495.1) at 0.281 mg/mL in a concentrated solution. (C22H36N2O5S.HCI.H₂O A solution for infusion is prepared by extracting 50 mL from a 250 mL bag of 5% glucose s and adding 50 mL of concentrated solution. Sonya who weighs weighs 60 kg requires a tirofiban dose of 0.4 mcg/kg/min for 30 minute- What volume would remain after 30 minutes? Answer: 94.53 mL X The correct answer is: 236 mLAssuming the molar extinction coefficient for para-nitrophenyl phosphate (PNP) is 55,290 mol "dm cm, calculate the concentration of the molecule that produced an absorbance of 0.770 OD units in a 1.5 cm cuvette. Show all working -1 3 -1