Part a through b please Part a) In the following alum synthesis reaction 1.50 grams of aluminum are reacted with excess base and acid. 2 Al + 2 KOH + 4 H2SO4 + 22 H2O → 3 H2 + 2 KAl(SO4)2·12H2O If 7.3 g of alum (molar mass = 474.41 g/mol) were collected from the above reaction, what is the percent yield of the reaction? a) 96. % b) 54. % c) 28. % d) 21. % Part b) The precipitate that would form when aqueous solutions of sodium sulfate and barium nitrate are mixed is, a) BaSO4 b) NaNO3 c) both BaSO4 and NaNO3 d) no precipitate forms
Part a through b please Part a) In the following alum synthesis reaction 1.50 grams of aluminum are reacted with excess base and acid. 2 Al + 2 KOH + 4 H2SO4 + 22 H2O → 3 H2 + 2 KAl(SO4)2·12H2O If 7.3 g of alum (molar mass = 474.41 g/mol) were collected from the above reaction, what is the percent yield of the reaction? a) 96. % b) 54. % c) 28. % d) 21. % Part b) The precipitate that would form when aqueous solutions of sodium sulfate and barium nitrate are mixed is, a) BaSO4 b) NaNO3 c) both BaSO4 and NaNO3 d) no precipitate forms
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.87PAE
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Part a through b please
Part a) In the following alum synthesis reaction 1.50 grams of aluminum are reacted with excess base and acid.
2 Al + 2 KOH + 4 H2SO4 + 22 H2O → 3 H2 + 2 KAl(SO4)2·12H2O
If 7.3 g of alum (molar mass = 474.41 g/mol) were collected from the above reaction, what is the percent yield of the reaction?
a) 96. %
b) 54. %
c) 28. %
d) 21. %
Part b) The precipitate that would form when aqueous solutions of sodium sulfate and barium nitrate are mixed is,
a) BaSO4
b) NaNO3
c) both BaSO4 and NaNO3
d) no precipitate forms
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