: P Note: You may assume you have an excess of either reactant if the reaction requires more than one of those molecules to form the products. In the drawing area below, draw the skeletal ("line") structures of the missing organic products X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. H+ H+ + -OH ☑ Y Predict the organic products that form in the reaction below: Click and drag to start drawing a structure.

w w w w w w w w w w w w TTTTTT M Balance the chemical reaction: C4H10) + O2(g) → CO2(g) + H₂O 17 What are the coefficients for the reactants and the products? A. 1+10 4+8 C. 2+13 8+10 B. 2+9 4+5 D. 2+9+8+20 Balance the chemical reaction: H₂PO4(aq) + Fe(s)→ H₂(g) + Fe3(PO4)2(s) 18 What are the coefficients for the reactants and the products? C. 2+2+2+3 D. 2+3 3+1 A. 1+2 2+1 B. 2+1 3+2 Activity Series of Metals lithium rubidium potassium barium Most reactive Least reactive strontium calcium sodium magnesium beryllium aluminum manganese zinc cadmium iron cobalt nickel tin lead (hydrogen) copper mercury silver palladium platinum gold Li Rb K Ba Sr Ca Na Mg Be Al Mn Zn Cd Fe Co Ni Sn Pb (H₂) Cu Hg Ag Pd Pt Au

Q1: The following reactions were found to occur while trying to make a desired product B A B -TAI=K₁AC₁ A-X -TA2 = K₂A CA A+X-Y -TA3=K3A CACX Species X and Y are both foul pollutants a) What is the point selectivity of B with respect to the foul pollutants X and Y? Plot the point selectivity as function of CA (CAo=1 M) at 300 K. b) How would you carry out this reaction to maximize the formation of B (type of reactor preferred)? Just give a recommendation based on (a). Additional Information -10,000/T KIA =.5 e min Tin degrees Kelvin -20,000/T K2A = 50 e min T in degrees Kelvin min¹, T in degrees Kelvin K3A = 100 e 5,000/T

1. Ammonia, NH3, is prepared by the following reaction: 2 NO2(g) + 5 H2(g) - 2 NH3(g) + 2 H2O(I) Calculate the percentage yield of ammonia in a reaction of 45.8g of NO and 12.4 g of H2? Show all the steps to obtain the final answer. 2. PBrs is prepared according to the following reaction: PBr3 + Br2 PBrs When 65.6 g of Br2 reacts with excess PB13, 125.2 g of PBrs is produced. Calculate the percentage yield for the reaction.