Mass of crucible, lid, and compound Trial 1 Trial 2 fired 10 min and cooled 20 min 1st mass measurement (g) 45.058 48.882 fired an additional 2 min and cooled 20 min 2nd mass measurement (g) 45.141 48.593 fired an additional 2 min and cooled 20 min 3rd mass measurement (g) 45.147 48.696 The crucible gained mass during the firing, what was added?
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Chemistry
Mass of crucible, lid, and compound Trial 1 Trial 2 fired 10 min and cooled 20 min 1st mass measurement (g) 45.058 48.882 fired an additional 2 min and cooled 20 min 2nd mass measurement (g) 45.141 48.593 fired an additional 2 min and cooled 20 min 3rd mass measurement (g) 45.147 48.696
The crucible gained mass during the firing, what was added?
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- 2a. Volume in graduated cylinder , indirect method - volume of a 400mL Beaker(2 methods) measure in to the 10ths place. Fill#1/Fill#2/Fill#3/Fill#4/Fill#5/= Total Volume . 2b. Direct Method ( use formula for the volume of a cylinder):V=nr(2)h {show work} Radius/ height/ n-3.1415/ Volume (n r2 h)AaBbCcDc AaBbCcDc AaBbC AABBCCC AaB Replace 1 Normal 1 No Spac... Heading 1 Heading 2 Title Dictate Sensitivity Editor ASelect v Paragraph Styles Editing Voice Sensitivity Editor C. Identify whether the substances listed below is an element (E), a compound (C), a Heterogeneous Mixture (HM), or a Solution (S) which is the same as homogeneous mixture. On the last column list TW0 physical properties of the substance. Physical Properties Element, Compound, Mixture, or Solution? Substances 1. Sausage 2. Steam 3. Salt Water 4. Pencil lead (Pb) 5. Soda 6. Silver (Ag) 7. Toothpaste (NazHPO4) 8. A burrito 9. LemonadeKernels of popcorn were weighed and then heated to pop. Water escaped in the process of popping. DATA DESCRIPTION TRIAL 1 TRIAL 2 Mass of Empty Evaporating Dish 35.6450g 35.6452g Mass of Evaporating Dish + Kernels Before Heating 42.3512 g 44.9572 g Mass of Evaporating Dish + Kernels After Heating 41.2540 g 42.6571 g What is the average percentage of water in the kernels? 65.180% 28.719% 21.208% 3.8913%
- 49) Calculate the length of a copper wire having a diameter of 0.200 cm and a mass of 15.620 g. The density of copper is 8.92 g/cm3. (Given: volume = 7 d2 L/4, where p = 3.14, d = diameter, and L = length) A) 1.80 x 10-4 cm B) 4.00 x 10-4 cm C) 1.75 cm %3D %3D %3D D) 5.50 × 10-2 cm E) 55.8 cmIt gives inacurate results For Wooden" sphere because wood haS the ability to absoro water (imbibition) Date For which object does the method of volume by displacement give an inaccurate result? Why? A4. Calculate the density of each object (use the volume by displacement determination of the volume for each object except the wooden sphere; for the wooden sphere use the volume calculated from the diameter). Show all work with units and record your answers in the table below to the correct number of significant figures and with proper units. pensitty=MassOF Substance VOIUME oF Substance Show work: Lead: 47.460905. 5SF IRON: 263:60955F ろろ。5 ML-るSF -니.2ML→25F =11.39/MLE119/ML %3D7.879/ML nkown sphere: 7.380g-05 4.2ML 2 golden nugget: 31.0094 *VolUMe OF WOoden Sphere: TS OFWOoden sph- ir=radius OF WOoden Sph. 8.99/ML 1.6ML2 %3D199/ML| Table 2: Density Results Object xx 27 CM3 bensity= 그9.170 g/ML=Ol0981 g/ML Calculated Density 119/ML 7.879/ML 0.698/ML 3.99/ML 199/ML lead sphere =113ML…3. A method of analysis yields masses of gold that are low by 0.4 mg. Calculate the percent relative error caused by this result if the mass of gold in the sample is a. 500 mg b. 250 mg c. 60 mg 4. The method described above is to be used for the analysis of ores that assay about 1.2% gold. What minimum sample mass should be taken if the relative error resulting from a 0.4-mg loss is not to exceed a. -0.1% b. -0.8%
- EJIYZPROfspoHcK3uA&lv=HbAhnaEn7foZmyeo a hjkml,/t[plkojihug. N Nitro Type | Compe.. E 3:28 Now playing. e QBA2 2020-2021 DO 12 13 14 15 16 17 18 19 20 21 21 of 21 Raymond went to the grocery store with his mom. He started by pushing an empty grocery cart with 0 kg of mass. As the shopping trip progressed, the cart increased in mass from 0 kg to 10 kg. Which argument below supports Raymond's claim that it was more difficult to push the 10 kg cart as opposed to the empty cart. O As the cart decreased in mass, Raymond had to use more force to push the cart. O As the cart increased in mass, Raymond had to use more force to push the cart. O As Raymond continued to push the cart during the duration of the trip, he became tired which made it more difficult to push the cart. O As Raymond continued to push the cart during the duration of the trip, friction began to build up on the wheels causing the cart to be more difficult to push.Estimated volume of crucible 25.0 mL measured volume of crucible 23.0 mL percent error of estimate (% error=accepted value-experimental value/accepted value ) volume in (use measured volume of crucibleto answer for the ): kL cL* Question Completion Status: QUESTION 3 A If 20.0 Cal make an ounce, how many ounces of formula should a baby drink per day if the energy need per day is 1.50 x 10³ Cal? Express answer to the correct number of significant figures. 75.0 x 10E3 ebapps~2Fblackboard~2Fcontent~2Flist Content.jsp%3Fcourse_id%3D_514... QUESTION 4 A 9.86 g sample of iron metal was heated in water to 85°C. Then, it was dropped into a beaker containing 240.0 g of H₂O at 28.5°C. Assuming that the water gained all the heat lost by the iron, what is the final temperature of the H₂O and Fe? If 756 cal of heat were added to 64.8 g of Al at 32.5 °C, what is the final temperature of the aluminum? 10
- 7. Air has a density of 0.001226 g/mL. What volume of air would have a mass of 1.0 lb? (1.0 Ig = 454 g) %3D A) 3.7 ml B) 7 mL C) 815.6 mL D) 37 mL E) 3.7 x 105 mL O a O b O c d.8) The vessel to be weighed should be placed of the pan. (off to the side, or in the center) 9) After heating a sample in a dish it will save time to weigh it immediately or cool it completely? 10) To avoid the errors in mass due to the use of balances that are not calibrated, one should weigh by a method called 11) If you weigh a hot object on the balance, the reading will be higher, the same, or lower than if it had been weighed after it cools to room temperature? (higher, the same, or lower) 12) If you weigh a cold object on the balance, the reading will be higher, the same, or lower than if it had been weighed after it warms up to room temperature? (higher, the same, or lower)DATA: Mass of potassium nitrate mass of test tube and potassium nitrate mass of test tube mass of potassium nitrate Volume of water taken Buret readings: Final gaml Initial Volume 4.97 added Temperature at which crystals appear Total volume of water in tube ML 1st addition 2nd addition 7.09ml 12.1ml 2.12 mal 7.09 ml 12.1ml 53.85839 43.9740g 9.9131 water. Record all data in the 4.97 9.98 15.78 4.97 9.98 3rd addition 17.9 ml 21.1ml 78.8 Temperature of water when volume is measured Density of water at when volume is measured (from reference) 0.970 Trial | || 52.0 39.1 21.4°C 15,18 4th addition 18.98 17.9ml ||| 28.2 18.98 IV 2