In lab, you will be given a stock solution that has a glucose concentration of 60 mg/dL. You need to make 1 mL of each of the following glucose concentrations: 0.94 mg/dL, 1.88 mg/dL, 3.75 mg/dL, 7.5 mg/dL, 15 mg/dL, and 30 mg/dL. Distilled water will be the solvent in these dilutions. Enter your numbers only

In lab, you will be given a stock solution that has a glucose concentration of 60 mg/dL. You need to make 1 mL of each of the following glucose concentrations: 0.94 mg/dL, 1.88 mg/dL, 3.75 mg/dL, 7.5 mg/dL, 15 mg/dL, and 30 mg/dL. Distilled water will be the solvent in these dilutions. Enter your numbers only

General, Organic, and Biological Chemistry

7th Edition

ISBN:9781285853918

Author:H. Stephen Stoker

Publisher:H. Stephen Stoker

Chapter8: Solutions

Section: Chapter Questions

Problem 8.42EP

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2. If a 50 mL solution of 2 mg/mL glucose has 20 mL of water added to it, have these changed? Please Underline (or circle) the correct answer. The concentration of the solution? Increased Decreased Stayed the same The grams of glucose in the solution? Increased Decreased Stayed the same The moles of glucose in the solution? Increased Decreased Stayed the same 3. If a researcher starts with 3.00 mL of a 4.50 mg/mL protein solution and adds 10.0 mL of water, what is the amount (mg) of protein in the diluted solution? vious pus
In lab, scientists often use percentages to describe concentration. When making a solution, percentage can be expressed as weight over volume (wt/vol) or as weight over weight (wt/wt). When expressing things as %(wt/w) it usually assumed that 1 mL of water = 1 gram of water. This is similar to assuming molarity (mol/L) equals molality (mol/kg) In lab, 70%(wt/vol) ethanol is frequently used to sanitize the lab þench or research tools such as forceps. In order to produce a final volume of 200 mL of 70%(wtvol) ethanol, how many mL of 99%(wt/vol) ethanol would you need to add? The percentages can be treated as a concentration. A solution that is 70% ethanol is 70 g of ethanol and 30 mL of water, or 70 g Ethanol out of 100 mL of solution. Therefore, it is possible to use m,v, = m,v2 and use the percentages as the concentration values. Report your answer rounded to two decimal places
The lab requires a 3.00 M HCI solution. How many mL of a 12.00 M HCI solution are required to produce 200. mL of this 3.00 M HCI solution? Please provide your answer to 3 significant figures. Add your answer
This lab used 6 M HCl that was diluted from a higher concentration. If your lab instructor asked you to make a solution of HCl with a concentration of 2.0 M from 50.0 mL of a 10.0 M stock solution of HCl, to what total volume would you have to dilute the portion of stock solution? Units as mL.
What is the volume in mL needed to prepare a 0.4 M NaOH solution using 1.6 g of NaOH? The molar mass of NaOH is 40.0 g/mol. Report your volume to a whole number (no decimal place) and only enter the numeric value, do not enter the unit.
Solution 1 is diluted by adding 519 microliters of Solution 1 to 5 mL of Solution 2. What is the dilution of Solution 1? Report your answer in standard decimal notation rounded to 2 decimal places. Include trailing zeros so that two decimal points are reported. For example, 500 μL added to 5 mL would be a 0.09 dilution or 50 μL added to 4.5 mL would be a 0.10 dilution.
Drink # Glucose Concentration in mM 1 2.455 mM 2 0.307 mM 3 3.750 mM 4 1.100 mM 5 1.500 mM From here, each group needs to convert the concentration of their drink from mM of the diluted drink into g/100mL of the undiluted drink. This is where you come in! The students are stuck at this point and really need your help! Main Goal: Convert the experimental glucose concentration (provided in the table below) from mM (millimolar) to g/100 mL. Hints & Tips Take the 1/100 dilution factor into consideration Molarity will open the doors for you to get to grams. Once at M assume 1L of solution. (Hint: this will help you when converting from M to moles) You will also need to calculate the molar mass of glucose which has the formula C6H12O6 There are 5 steps in total Task 1: Write a step-by-step guide with key words for the Chem 2 students on how to do these calculations. You can use diagrams, a table or just type the steps out. Ensure the steps…
6. Suppose you start with 100 mL of a 5% (5g/dL) sucrose solution and dilute it by adding 300 mL of distilled H20. a) What is the total volume of the new solution in mL? b) What is the sucrose concentration of the new solution in mg/dL? c) How many grams of sucrose are contained in the total volume of this solution?
In the dilution of Solution B, if the original stock solution has a concentration of 0.8 M, what is the concentration (M) of the new dilution after adding 6 mL of water? ANSWER MUST BE ROUNDED OFF TO TWO (2) DECIMAL PLACES. Water to be added Solution B 10 mL 10 mL 10 mL 10 mL 10 mL 10 mL Add your answer 0 mL 2 mL 4 mL 6 mL 8 mL 10 mL Concentration 0.8 M
Table 1. Standardization of HCI Solutions (40 pts) Trial Volume of HCI (To the nearest 0.01 mL) Molarity of NaOH (mol/L) Volume of NaOH (To the nearest 0.05 mL) Molarity of HCI* (mol/L) 1 20.00 mL 0.01011 10.40 0.0525 2 20.00 L 0.01011 10.50 0.0530 3 20.00 ml 0.01011 10.50 0.0535 4 20.00 mL 0.01011 10.60 0.0535 5 (If necessary) 20.00 mL 0.01011 10.50 0.0530 *Show calculations. Attach additional sheets of papers. According to experiment, the average molarity of our HCI solution is 0.0531 ± The uncertainty should cover the range of the experimental values. mol/L.
Muriatic acid is the commercial name for hydrochloric acid that can be purchased from hardware stores as a solution that is 37 % (w/w) HCI. What mass of this solution contains 7.5 g of HCI? Part 1 Your answer is correct. To begin this problem, one must find a way to relate the percentage by weight of HCI to grams of the solution. To do this, assume 37 g of HCI per 100 g of solution. eTextbook and Media Attempts: 1 of 15 used Part 2 Your answer is correct. Set up an equation to solve for grams of solution. 8 soln 8soln = SHCI 8HCI 8soln = (8HCI 8 solr 8roln = (8Hci) [(8som ) (8ncı)] Attempts: 1 of 15 used Part 3 Input the appropriate values to solve for the mass of a 37% (w/w) solution of HCI that contains 7,5 gof HCI? g solution Save for Later Attempts: 0 of 15 used Submit Answer
What mass of HCl is contained in 27.1 mL of an aqueous HCl solution that has a density of 1.19 g/mL and is 37.21% HCl by mass? mass = ___ g