Given the following transportation network and the production/attraction data in each zone. 3 min 3 min 4 min 4 min 2 min 3 min 4 min 7 min Production/Attraction Table Zone 1 2 3 4 5 Production Attraction 600 1000 500 300 200 350 400 The number of trips that originates from Zone 3 and ends in Zone 1 is 13 88 29 None of the above 2.
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- Given the following transportation network and the production/attraction data in each zone. 4 min 1 3 min 2 min 3 min 5 7 min 4 min 4 min Production/Attraction Table 3 249.4 180.0 163.5 None of the above 2 3 min Zone 1 2 3 4 5 Production 600 475 1000 500 300 Attraction 400 200 100 420 0 The number of trips originating from Zon2 3 and ending in Zone 5 isGiven the following transportation network with travel time in minutes: 3 2 2. 3 4 3 The trip production from TAZ 3 is 1,000. The trip attractions from TAZ 3 to all other zones are shown below: From/To 1 500 2 300 4 Trip Attraction 300 The minimum path from zone 3 to zone 1 is: Links 3-4, 4-1 5 min Links 3-2, 2-1 Link 3-11. Planners have estimated the following models for the AM Peak Hour T₁ = 1.5 H₁ T; - (1.5 Euj1) + (1 Euthy) + (0.5 Eretj) Where: T - Person Trips Originating in Zone i T₁ = Person Trips Destined for Zone j H Esti Eath Eret Variable 10000 8000 3000 2000 Data Dakotopolis 15000 10000 5000 1500 New Fargo A. What are the number of person trips originating in and destined for each city? B. Normalize the number of person trips so that the number of person trip origins = the number of person trip destinations. Assume the model for person trip origins is more accurate.
- The present trip ends and travel time matrix between the zones are shown in Tables 6.75 and 6.76, respectively. Travel impendance factor between the zones may be assumed to be e-ti. The socio-economic adjustment factors between the zones may be assumed to one. Calculate the trip interchanges between the zones by using the gravity model. TABLE 6.75 Zones Trips produced Trips attracted 1 2 3 2500 3300 3200 TABLE 6.76 1 2 3 1-15 20 2 15 10 3 20 10 I 3000 4000 2000A Study area with four transportation analysis zones has the following information: Table 3: Trip productions and attractions for a four-zone study area and travel time between zones. Travel Time, (t) (min) Zone Trip productions Trip I 220 2 240 3 330 4 230 attractions 350 270 210 190 Table 4: Travel time versus friction factor. Time (min) 2 Friction Factor 61 1 78 from zone 1 4 9 10 6 3 47 4 37 from zone 2 5 29 5 6 7 5 6 22 from zone 3 7 17 6 8 7 6 8 14 from zone 4 9 10 8 9 11 7 10 8 Using a gravity model, determine the number of trips from zone to zone through two iterations. (Assume that the socioeconomic adjustment factor is 1.0).2. A four zones city has two residential zones A and B, generating 725 and 575 trips, respectively. These trips go to two employment zones C and D, attracting 875 abd 425 trips respectively. The travel time, friction factors, between zones is given as Route AC AD BC BD Travel Time 8 15 10 13 Friction Factors 90 10 60 50 (a) Estimate the trips generating from A and B respectively (b) The OD survey that was performed for this city indicates that the actual number of trips on each route was as follows, AC=650, AD=75, BC-400 and BD = 175. (c) Determine the new friction factor Fij in order the replicate the actual trip movements.
- The trip generation process has produced home-based work productions and attractions for zones 1 through 5. Rectify the unbalanced HBW trips. ZONE PRODUCTIONS ATTRACTIONS 1 420 410 > 2 160 150 230 280 4 210 200 120 1604. The present trip ends and travel time matrix between the zones are shown in Tables 6.75 and 6.76, respectively. Travel impendance factor between the zones may be assumed to be e-tij, The socio-economic adjustment factors between the zones may be assumed to one. Calculate the trip interchanges between the zones by using the gravity model. TABLE 6.75 Zones Trips produced Trips attracted 1 2500 3000 2 3300 4000 3 3200 2000 TABLE 6.76 1 2 3 1 15 20 2 15 10 3 20 10A small town has two residential zones, A and B producing 900 and 600 work trips respectively. Zones C, D and E are work opportunity zones attraction 900,400 and 200 trips. The travel times between the zones and actual obsrved trips are as shown in the attachment below;
- Problems 2. Solve for the best choice in terms of utility U=A-0.05X1 -0.02X2 3. For 300 trips, assign them using constant assignment ratio. Route 1 2 3 4 5 M Mode A Car -0.6 Jeep -0.3 Grab -0.4 Bus -0.5 Hours 1.1 1.2 1.3 1.4 1.5 X1 50 10 70 30 X2 30 45 20 35a) Table 4 indicates an urban zone’s expected household composition at some future year and the calibrated educational-based trip rates. Estimate the total educational-based trips in terms of "y" that the urban zone will produce on a typical day in the horizon year. (A Table 4: Household composition and trip generation rates Number of motor vehicles per household Number of persons per household 1 2793 1.7y 4 5+ 2046 H. 344 2472 3092 R 0.8y 2.Зу 717 3.1x 2.4y 1022 3.1x 2.4y 726 2+ H 294 2.1x R 1.6x 3.3х H= Number of households in category R= Educational trip production rate (per household) in category x-0.5yQ1. The following is the number of trips and the number of households by the number of persons per household and the level of household income in a given zone. Persons/hh 1 2 3 4 5 or above Low Persons/household 1 2 3 4 5 or more No. of hh Trip No. No. of hh 93 222 149 72 341 138 59 417 125 120 1010 109 13 107 37 Income Medium The forecasted number of households in the study area for a target year is shown below. Low 120 100 90 150 30 Trip No. 616 853 1025 1186 457 High No. of hh Trip No. 96 360 27 205 33 381 40 471 33 423 Income Medium 280 220 190 180 60 High 130 40 50 70 60 (a) Calculate the forecasted number of trips for each combination of the number of persons per household and the level of household income. (b) Alternatively, trip rate can be estimated using the following linear regression equation. Trip rate=0.46+ 1.96 × NPERSON + 1.66 x HINCOME Where NPERSON = no. of persons per household (= 5 for 5 or more persons in household); HINCOME = level of household income (= 0 for low…