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Find the general solution x = ([2, -5],[1, 2])x+ ([0], [cost]), 0Answer is : x = c1[5cos(t), 2cos (t) + sin(t)] + c2[5sin(t), -cos(t) + 2sin(t)] + [0,1/2]t*cos(t) - [5/2,1]t*sin(t)- [5/2, 1]cos(t) HOW DO I GET THIS ANSWER

Find the general solution x = ([2, -5],[1, 2])x+ ([0], [cost]), 0Answer is : x = c1[5cos(t), 2cos (t) + sin(t)] + c2[5sin(t), -cos(t) + 2sin(t)] + [0,1/2]t*cos(t) - [5/2,1]t*sin(t)- [5/2, 1]cos(t) HOW DO I GET THIS ANSWER

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter9: Multivariable Calculus
Section9.2: Partial Derivatives
Problem 28E
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Find the general solution x = : ([2, -5], [1, -2])x+ ([0], [cost]), 0Answer is : x = c1[5cos(t), 2cos (t) + sin(t)] + c2[5sin(t), -cos(t) + 2sin(t)] + [0,1/2]t*cos(t) - [5/2, 1]t*sin(t) - [5/2, 1]cos(t) HOW DO I GET THIS ANSWER 8. x' 3 c -5 0 = (₁-2) x + (+), 0 COS 0<t<π
Transcribed Image Text:Find the general solution x = : ([2, -5], [1, -2])x+ ([0], [cost]), 0Answer is : x = c1[5cos(t), 2cos (t) + sin(t)] + c2[5sin(t), -cos(t) + 2sin(t)] + [0,1/2]t*cos(t) - [5/2, 1]t*sin(t) - [5/2, 1]cos(t) HOW DO I GET THIS ANSWER 8. x' 3 c -5 0 = (₁-2) x + (+), 0 COS 0<t<π
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