Find sec42x -dx tan 2x A --—-—-cot²2x-—-—-cot³21+ C 16 cot82x) (4sec22x-1) B -(cort2x) 4 12 11 1 C) + +C 12 tan 2x 16 tan³2r Ⓒ - - (cor³2() (1+36x²2x) + C D $2x) +C +C

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.4: Fractional Expressions
Problem 59E
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Question
S
Find
sec42x
-dx
tan 2x
A - 1/2 c01²³2x-
—cot²2x===cot³21+ C
16
cot82x (4sec 22x-1)
B
- (2x)
4
12
1
C
12 tan 2x
D
(cot62x)
- (cors
1
16 tan 82x
1+3csc²2x
12
+
+C
+C
+C
Transcribed Image Text:S Find sec42x -dx tan 2x A - 1/2 c01²³2x- —cot²2x===cot³21+ C 16 cot82x (4sec 22x-1) B - (2x) 4 12 1 C 12 tan 2x D (cot62x) - (cors 1 16 tan 82x 1+3csc²2x 12 + +C +C +C
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