D. Find dy/dx of the following and simplify x v4-x y= Arccos

Q: Find dy/dx in terms of t if x=te^t , y=6t+6e^t dy/dx=

A: Use Product rule of derivative and find the derivative of x with respect to "t".

Q: find dy/dx in terms of x and y if arctane(x^3 y)=xy^3

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Q: dy xe dx to

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Q: Evaluate dy/dx at x = 2.5, correct to 3 significant figures, given y= (2x^2+3)/In 2x

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Q: dy Find dx from the equation y = sin[cos xy].

A: Explanation of the answer is as follows

Q: dy/dx of y=x arcsec(xy)

A: To Find: differentiation of y=x arcsec(xy)

Q: dy Q2 Find dx of x = tan(y)?

A:

Q: -1 dy find dx If y = %3D (1-VE)

A:

Q: Find dy/dz in terms of e and y if arctan(x®y) = ry°. ||

A: See the details solution in below

Q: dy Find for the following function. dx y = 5 sin x cos x dy dx II

A: We have to find the derivative of given function. We will use formula for product of function.

Q: Find dy/dx in following. )y=x' costx + xsin?x -2

A: Since you have asked multiple questions in a single request, we would be answering only the first…

Q: 3. Given y = (1- V2x); Find dy/dx %3D du

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Q: Find the value(s) of dy/dx  at y=1 given that x2y + y2 = 5.

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Q: if y= T-x x sinx dy , find V1-x² dx

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Q: Find of the following. dx Įx = VI-t ly = VI+t 1. 3t 1+t3 2. 3t2 y = 1+t3 t + -1

A: This question is based on Derivative of parametric function.

Q: y = cot-1(4-3x2)

A: y=cot-1(4-3x2)differentiate w.r.t.xwe know…

Q: y = sin (2x) + et ,Find dy Inx dx

A: 1. Differentiation can be defined as a derivative of a function with respect to an independent…

Q: Find dy/dx: y = Arctan (x/2)

A: You know: ----------------------------------------------------------------------

Q: x +1 dy =? find y = In x – 1 dx

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Q: Find dy and simplify whenever possible. dx 1. y = arcsin V4-x2 2. y = In(e¬* + xe¯*)

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Q: Find the dy/dx given that y = (sin x)x

A: The given value of y is, y = (sin x)x

Q: Find dy/dx for the following function. y=x2cos x sin x

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Q: Q2: a) Find dy/dx for xy cot(xy)?

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Q: Find d X Sin y = YCOS 2X at 店 %3D

A: Topic = Derivative

Q: Find for the following function. dx y= 5x° cos x sin x dy dx II

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Q: b) Find fo dy for y = Vt-1 t = sec?x sint

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Q: Given that x cos y + y cos x = 1, find dy/dx.

A: Given that, xcosy+ycosx=1. The objective is to find the implicit differentiation of xcosy+ycosx=1…

Q: dy Find dx for y = (1+ æ)* || Ans=

A: Here we can find the derivative as below.

Q: Find dy/dx in terms of x and y if arctan(x*y) = y“. dy dr

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Q: a dy Find given y = 4 In da

A: The given function,   y=4x lnx

Q: dy Find for the following function. dx y = 5 sin x+2 cos x dy dx II

A: Given that          y = 5 sinx + 2 cosx  Here we have to find dy/dx .

Q: 13. Find dx/ dt and at di/a dx in terms of x when x'6t=18 x'6t= 18

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Q: Given y=−3cosx, what is dy/dx?

A: y=-3cosx

Q: find dy/dt y=cos^2(cot^7t)

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Q: find  dy/dx by the implicit differenation, sin(xy) = cos(x+y)

A:

Q: e^(x)cos(y)=1+sin(xy) dy/dx?

A: To differentiate :

Q: Q3: dy\dx off(x)= tan x cot x is

A: Given,    f(x) = tan(x) cot(x)         = 1   As we know, inverse of tan(x) is cot(x).

Q: dy y%3D 1+sinx cos x lb) find dx

A: Given

Q: Find dy/dx for the following Function y = tan (In xr)

A: The chain rule is a formula to calculate the derivative of a composition of functions. It states…

Q: Hiw@ Find dy for the dollowinge りょ CasX +x+ 2) 1 = TE よ + Sec( x) TT InX + T +linx)

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Q: d 2x Le arctan t dt dx

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Q: dy In y ,if cot6x - 2x'y+ xe' = 20cos2y– dx Find

A: We have to find dydx, if cot6x-2x3y+xey=20cos2y-lny2.

Q: Find dy/dx: y = Arctan (2/x)

A: Given function is y=arctan2x

Q: Differentiate y=arccos(e^(3x)) dy/dx=____________

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Q: dz i. y = e? sin x + In x (arcsin z) with = 4 dx

A: It is given that,  Therefore now take the derivative of the given function. So,

Q: dy dx? Find where vy +xy = 3.

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Q: Ql find dy 2メ for y= cos ( Inx + e %3D dx

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Q: 36 sin t Given x = 6t – 15 and y dy dx dy dx?

A: Explanation of the solution is given below...