Create a program in MIPS Assembler that allows you to create the following sequence of numbers: 3 6 9 12 15 18 21 24 27 30 Using a branch statement
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- Write the MIPS assembly code which calculate the grades of student according to the criteria: When the mark is greater or equal to 90, it will return the value 4 if the mark is greater or equal to 80 but less than 90, it will return the value 3 if the mark is greater or equal to 70 but less than 80, it will return the value 2 if the mark is greater or equal to 60 but less than 70, it will return the value 1 if the mark is less than 60, it will return the value 0Write a program in MARIE assembler that calculates a product (multiplication) of 2 numbers: A=B*C The program needs to allow for input of 2 decimal numbers ( must be negative or 0) in the INPUT and output the product of multiplication in the OUTPUT window.Write a program in MIPS Assembler that allows you to perform the following arithmetic operation: a=b+c d = e + f g = a - d Where b, c, e and f must be integers entered by console The result (g) must also be displayed by console
- TASM/Assembly language Write a program using turbo assembler in which will read two decimal numbers, then multiply them together, and finally print out the result (in decimal).MIPS Assembly Write a program for RISC MIPS 32bits that challenges a person to guess a number of up to 3 digits before and 3 digits after the comma, that is, a value between 000,000 and 999,999. The program user will try to guess the number with multiple attempts, where the program will indicate at each attempt if the informed number is bigger, smaller, or if the user guessed correctly. When this happens, the program ends, showing a SUCCESS message and a total count of the number of attempts taken to get it right. The program must have a SUBROUTINE as described below. SUBROUTINE:- Input Parameters: user guess, expected value- Output: message on screen (bigger, smaller, SUCCESS)- Returns: value 1 if correct, 0 if incorrectWrite an assembly language program that adds 27345, 28521, 29533, 30105, and 32375 [only by using LOOP]
- This is COmputer Architecture! this is about hamming code PLEASE WRITE THE CODE IN MIPS ASSEMBLY LANGUAGE! Assignment for Computer Architecture The assignment is to create a MIPS programs that the determines what the ECC code should be for a given number (an 8-bit byte). ECC Hamming codes are explained on pages 420-424 in your text. The codes you create are to work for 8-bit positive numbers as these are simpler to work with than larger numbers. The program is to request the user to enter a byte of data (a positive integer in the range of 0 to 255 in decimal) and then create the 12-bit Hamming code as described in your text (see above). The program is to then output this (with an appropriate label) in hex. Requirements: Make certain that you have lots of comments in your code as this is in MIPS. Also make the code neat: line up the instruction columns, the register columns, and the comment fields For this assignment, turn in your code, a screenshot showing a working for a test…Select common examples of when an assembly programmer would want to use the stack: to pass arguments to save return address for CALL local variables temporary save area for registers applications which have FIFO nature, such as customers waiting in a bank queueReview the following snippet from an assembly code listing file (source assembly statements and listing file line numbers are removed purposely) and answer the questions. 00000000 B8 00000000 00000005 03 05 0000000A R 0000000B 66| 2B 15 00000008 R 00000012 41 00000013 69 15 0000000A R FFFFFED9 0000001D 8A C3 0000001F FF OD 0000000A R 00000025 661 B9 0019 1) Locate the instruction that has the smallest size object code (i.e. minimum byte-length), what is the corresponding address of the instruction? type your answer... 2) Locate the instruction that has the largest size object code (i.e. maximum byte-length). What is the byte-length of the instruction? type your answer... 3) How many of the above instructions have direct memory reference? choose your answer... 4) What is the total length (number of bytes) of the above object code snippet? type your answer... 5) How many instructions contain an opcode prefix? choose your answer...
- Programming Project: For Loops Write an Assembly Language Program that produces the Times Table for a specific integer value between 1 to 12. NOTE: You choose and hard code only one value (i.e. 7) and produce the times table for that value. Also note that since you are using registers and memory locations make sure that at each step you screen shot each result for each part of the Times Table. For example 7 x 12 = 84 but in Hexadecimal the value is 54. Sample code in C #include void main() ( int i, j; printf("Enter an integer: "); scanf("%d", &i); printf("Times %d Table\n", i). for(j = 0; j<= 12; j =j+1) { printf("%d x %d = %d\n", j, 1. j'i); } printf("\n");int total; int i; total = 0; for (i = 10; i > 0; i--) { total + i; } The following translates this into ARM assembler: /* -- sum-to-ten.s */ .text .global start _start: mov rº, #0 mov r1, #10 again: end: add r0, r0, r1 subs r1, r1, #1 bne again mov r7, #1 swi 0 @r0 := 0 @r1 = 10 @r0 := r0 + r1 @ r1 := r1 - 1 @loop again if we haven't hit zero @setup exit @exit In the above assembly language program, we first use the MOV instruction to initialize RO at O and R1 at 10. The ADD instruction computes the sum of RO and R1 (the second and third arguments) and places the result into RO (the first argument); this corresponds to the total += i; line of the equivalent C program. Note the use of the label at the beginning of the ADD instruction. The label is simply the relative memory address of where that instruction is when the assembler loads it into memory. The subsequent SUBS instruction decreases R1 by 1. To understand the next instruction, we need to understand that in addition to the…Basic ARM assembly please, new to the language: Write an ARM assembly subroutine which, given the values of x and y in r0 and r1, respectively, calculates the expression: x3 + 6x2y + 12xy2 + 8y3, saving the result in r2. You don’t have to check for overflow (i.e. the solution and intermediate steps are okay to be bound to 32- bits). Hint: High-school algebra will make the solution much simpler.