Consider a Markov chain with state space {1,2,3} and transition probabilities P13 = P21 = P32 = 0 and all other transition probabilities are 1/2. What is the long-run proportion of time that this chain spends in state 1? 1/3 1/2 It depends on which state the chain starts in. 2/3

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A: We have given that  Mean = 10 Standard deviation = 0.51 z = (x-μ)/σ

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A: From the given information we find the solution.

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A: Here's, we company two tailed value with one tailed value.

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A: Suppose an independent sample (X1, X2, X3) is taken from a random variable X having mean u and…

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A: Given information: Total number of cards in the deck = 52 Number of spades in the deck = 13 Number…

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