A car was valued at $44,000 in the year 1992. The value depreciated to $14,000 by the year 2004. Use the compund interest formula S = P(1 + r) to answer the following questions. A) What was the annual rate of change between 1992 and 2004? T = Round the rate of decrease to 4 decimal places. B) What is the correct answer to part A written in percentage form? %. T = C) Assume that the car value continues to drop by the same percentage. What will the value be in 2008 ? value = $ Round to the nearest 50 dollars.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
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Chapter7: Exponents And Exponential Functions
Section: Chapter Questions
Problem 68SGR
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A car was valued at $44,000 in the year 1992. The value depreciated to $14,000 by the year 2004.
Use the compund interest formula S
=
P(1 + r) to answer the following questions.
A) What was the annual rate of change between 1992 and 2004?
7 =
Round the rate of decrease to 4 decimal places.
B) What is the correct answer to part A written in percentage form?
7 =
%.
C) Assume that the car value continues to drop by the same percentage. What will the value be in the year
2008 ?
value = $
Round to the nearest 50 dollars.
Transcribed Image Text:A car was valued at $44,000 in the year 1992. The value depreciated to $14,000 by the year 2004. Use the compund interest formula S = P(1 + r) to answer the following questions. A) What was the annual rate of change between 1992 and 2004? 7 = Round the rate of decrease to 4 decimal places. B) What is the correct answer to part A written in percentage form? 7 = %. C) Assume that the car value continues to drop by the same percentage. What will the value be in the year 2008 ? value = $ Round to the nearest 50 dollars.
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