8 Explain why the form 1 is indeterminate and cannot be evaluated by substitution. Explain how the competing functions behave. Choose the correct answer. OA. If lim f(x)=1 and lim g(x)=co, then f(x)9(x)1 as xa, which is meaningless. Therefore, substitution cannot be used. xa x-a OB. If lim f(x)=1 and lim g(x)=co, then f(x)9(x) as xa, so the limit does not exist. Therefore, substitution cannot be used. x-a xa OC. If lim f(x)=1 and lim g(x) = oo, then f(x)oo as x-a, so the limit does not exist. Therefore, substitution cannot be used. x-a x-a D. If lim f(x)=1 and lim g(x) co, then f(x)9(x)0° as x-a which is meaningless. Therefore, substitution cannot be used. x-a х-а

8 Explain why the form 1 is indeterminate and cannot be evaluated by substitution. Explain how the competing functions behave. Choose the correct answer. OA. If lim f(x)=1 and lim g(x)=co, then f(x)9(x)1 as xa, which is meaningless. Therefore, substitution cannot be used. xa x-a OB. If lim f(x)=1 and lim g(x)=co, then f(x)9(x) as xa, so the limit does not exist. Therefore, substitution cannot be used. x-a xa OC. If lim f(x)=1 and lim g(x) = oo, then f(x)oo as x-a, so the limit does not exist. Therefore, substitution cannot be used. x-a x-a D. If lim f(x)=1 and lim g(x) co, then f(x)9(x)0° as x-a which is meaningless. Therefore, substitution cannot be used. x-a х-а

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter3: Functions And Graphs

Section3.5: Graphs Of Functions

Problem 37E

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