4. Find the phasors corresponding to the following a. v(t) = 21 cos(4t – 15°)V b. i(t) = -8 sin(10t + 70°) mA
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Step by step
Solved in 3 steps
- Convert the following phasors into sinusoidal waveforms a. Vi = 100e30 V, w= 10' rad/s b. Vi = 120e45 V, w= 10³ rad/s c. I = 100e*45 A, w= 2*10 rad/s d. I1 = 240e 26.6 mA, w= 2*10* rad/s %3DWhat is the phase relationship between the following waveforms? v = 10 V sin(@t + 60°) i= 2 mA sin(@t – 15°) -The r.m.s. value of a sinusoidal current of maximum value 45 A is,
- Question 1: what is the phase relationship between the sinusoidal waveforms of each of the following sets? v = 10 sin(oot +20°) i=5 sin(of - 50°)For the component shown in figure, find the sinusoidal current i using phasors. i C = 0.47 µF V f = 1 kHz %3DI) Convert the following phasors to the time domain if the frequency is I KHz. . h-3 A a) k- 12 /40 b)
- 1) For the following waveforms; i= -2sin (wt+20°) v = 5sin (wt+10°) The phase relationship between the waveforms is: a) v lags i by 170° b) i leads v by 160° c) v leads i by 170° d) v leads i by 160°Given V 20 sin(@t + 60°) and V2 = 60 cos(ot- 10°). What is the phase angle %3D between the waveforms? All terms to be expressed in cosine terms. 60 80 20 40 Moving to another question will save this response. a hp O O OQuestion2): Find the current and voltage for each element in the circuit shown and sketch the sinusoidal waveform X = 60 Xc = 10 N ll + VL - R = 40 + UR - e = 70.7 sin 377t (^ ZT
- 2. A series RL circuit has voltage and current equations of e = 141.42 sin 2n30t + 141.42 sin 2n90t volts and i = 9.8 sin (2n30t - 30°) + 5.66 sin (2n90t - 60°) amperes. Determine the inductance L. A. 92.5 mH B. 38.3 mH C. 27.22 mH D. 83.49 mHFor the pairs of sinusoids, determine which one LAGS by how much a. e = 10cos(4t – 60°) V and i = 4sin(4t + 50°) A b. e = 4cos(377t + 10°) V andi = -20coswt A Draw the phasor diagramFind a single sinusoid corresponding to: I= -2j +10/-45° i(t)=I,cos(@t+D) , D=(......)°