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4. Design a low-pass filter circuit that has the transfer function. Assume all capacitors to be 0.1µF. Final answer should be a circuit. -6283 H¿(s) = (s + 628)(s² + 628s + 6282) Table 16.3-2 Denominators of Butterworth Low-Pass Filters with a Cutoff Frequency we = 1 rad/s ORDER DENOMINATOR, D(S) s+1 2+1414s +1 (s+1)(s? +s+ 1) 4 (2 +0.765s + 1)(s + 1.848s + 1) (s+ 1)(s +0.618s + 1)(s + 1.618s + 1) (s? +0.518s + 1)(s +1.414s + 1)(s + 1.932s +1) (s + 1)(s +0.445s + 1)(s + 1.247s+ 1)(s + 1.802s +1) 6. (s +0.390s + 1)3 +1.111s + 1)(s² + 1.663s + 1)(s? + 1.962s + 1) (s +1)(s +0.347s + 1)(s +s+1)( +1.532s + 1)(s?+ 1.879s + 1) (s?+0.313s + 1)(s? +0.908s + 1)(² + 1.414s + 1)(s? + 1.782s + 1)(s² +1.975s + 1) 8 9 10 Table 16.4-2 Sallen-Key Filters FILTER TYPE CIRCUIT DESIGN EQUATIONS RC Low-pass RC High pass A- 1DR RC Band-pass 2RS A- 1)R A AQ RC Band-stop (notch) A- IR

4. Design a low-pass filter circuit that has the transfer function. Assume all capacitors to be 0.1µF. Final answer should be a circuit. -6283 H¿(s) = (s + 628)(s² + 628s + 6282) Table 16.3-2 Denominators of Butterworth Low-Pass Filters with a Cutoff Frequency we = 1 rad/s ORDER DENOMINATOR, D(S) s+1 2+1414s +1 (s+1)(s? +s+ 1) 4 (2 +0.765s + 1)(s + 1.848s + 1) (s+ 1)(s +0.618s + 1)(s + 1.618s + 1) (s? +0.518s + 1)(s +1.414s + 1)(s + 1.932s +1) (s + 1)(s +0.445s + 1)(s + 1.247s+ 1)(s + 1.802s +1) 6. (s +0.390s + 1)3 +1.111s + 1)(s² + 1.663s + 1)(s? + 1.962s + 1) (s +1)(s +0.347s + 1)(s +s+1)( +1.532s + 1)(s?+ 1.879s + 1) (s?+0.313s + 1)(s? +0.908s + 1)(² + 1.414s + 1)(s? + 1.782s + 1)(s² +1.975s + 1) 8 9 10 Table 16.4-2 Sallen-Key Filters FILTER TYPE CIRCUIT DESIGN EQUATIONS RC Low-pass RC High pass A- 1DR RC Band-pass 2RS A- 1)R A AQ RC Band-stop (notch) A- IR

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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4. Design a low-pass filter circuit that has the transfer function. Assume all capacitors to be 0.1µF. Final answer should be a circuit. -6283 H¿(s) = (s + 628)(s² + 628s + 628²) Table 16.3-2 Denominators of Butterworth Low-Pass Filters with a Cutoff Frequency we = 1 rad/s ORDER DENOMINATOR, D(S) s+1 2+1.414s +1 (s+ 1)(s² +s+ 1) (s? +0.765s + 1)(s + 1.848s + 1) 3 4 (s+ 1)(s² + 0.618s + 1)(s² + 1.618s + 1) (s? +0.518s + 1)(s² + 1.414s + 1)(s² + 1.932s + 1) (s +1)(s? + 0.445s+ 1)(² + 1.247s+ 1)(s² + 1.802s +1) (s +0.390s + 1)?+1.111s+ 1)(s² + 1.663s + 1)(s²+ 1.962s + 1) (s +1)(s? +0.347s + 1)( +s+1)(² + 1.532s + 1)(s+ 1.879s + 1) (s?+0.313s + 1)(s² + 0.908s + 1)(s² + 1.414s + 1)(s² + 1.782s + 1)(s² +1.975s + 1) 6. 7 8 9 10 Table 16.4-2 Sallen-Key Filters FILTER TYPE CIRCUIT DESIGN EQUATIONS RC Low-pass CA - 1IR RC High-pass R2 A- DR RC Band-pass 2RS A- 1DR A AQ RC Band-stop (notch) A- IN
Transcribed Image Text:4. Design a low-pass filter circuit that has the transfer function. Assume all capacitors to be 0.1µF. Final answer should be a circuit. -6283 H¿(s) = (s + 628)(s² + 628s + 628²) Table 16.3-2 Denominators of Butterworth Low-Pass Filters with a Cutoff Frequency we = 1 rad/s ORDER DENOMINATOR, D(S) s+1 2+1.414s +1 (s+ 1)(s² +s+ 1) (s? +0.765s + 1)(s + 1.848s + 1) 3 4 (s+ 1)(s² + 0.618s + 1)(s² + 1.618s + 1) (s? +0.518s + 1)(s² + 1.414s + 1)(s² + 1.932s + 1) (s +1)(s? + 0.445s+ 1)(² + 1.247s+ 1)(s² + 1.802s +1) (s +0.390s + 1)?+1.111s+ 1)(s² + 1.663s + 1)(s²+ 1.962s + 1) (s +1)(s? +0.347s + 1)( +s+1)(² + 1.532s + 1)(s+ 1.879s + 1) (s?+0.313s + 1)(s² + 0.908s + 1)(s² + 1.414s + 1)(s² + 1.782s + 1)(s² +1.975s + 1) 6. 7 8 9 10 Table 16.4-2 Sallen-Key Filters FILTER TYPE CIRCUIT DESIGN EQUATIONS RC Low-pass CA - 1IR RC High-pass R2 A- DR RC Band-pass 2RS A- 1DR A AQ RC Band-stop (notch) A- IN
Table 16.5-2 First-Order Filter Stages FILTER TYPE FIRST ORDER CIRCUIT DESIGN EQUATION HG) =+P where 1 p= R2C Reminder! R1 R2 Low-pass in this table and for the low RC pass filter k is not the gain of this filter as it is R1 R2 where 1 p= RC High-pass and R2 in other R1 tables. Table 14.2-1 Laplace Transform Pairs f(t) for t>0 F(s) = L[f(1}u(t)} 8(4) 1 1 u(t) 1 e-at s+a 1 n! n! (s + a)"+1 sin (ot) s2 + w2 cos (wt) s2 + w2 at e sin (@t) (s +a)? + w2 s+a e-at cos (wt) (s + a)? + w?
Transcribed Image Text:Table 16.5-2 First-Order Filter Stages FILTER TYPE FIRST ORDER CIRCUIT DESIGN EQUATION HG) =+P where 1 p= R2C Reminder! R1 R2 Low-pass in this table and for the low RC pass filter k is not the gain of this filter as it is R1 R2 where 1 p= RC High-pass and R2 in other R1 tables. Table 14.2-1 Laplace Transform Pairs f(t) for t>0 F(s) = L[f(1}u(t)} 8(4) 1 1 u(t) 1 e-at s+a 1 n! n! (s + a)"+1 sin (ot) s2 + w2 cos (wt) s2 + w2 at e sin (@t) (s +a)? + w2 s+a e-at cos (wt) (s + a)? + w?
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