30 ml of 0.075 M sodium chloride solution from a 15 M stock solution = C1 x V1 = C2 x V2 = (15 M) (V1) = (0.075 M) (30 mL) =V1= 2.25 mL /15 M =0.15 mL Therefore, the student must add 0.15 mL of solution to water using

Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Mark S. Cracolice, Ed Peters
Chapter3: Measurement And Chemical Calculations
Section: Chapter Questions
Problem 61E
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30 ml of 0.075 M sodium chloride solution from a 15 M stock solution
= C1 x V1 = C2 x V2
= (15 M) (V1) = (0.075 M) (30 mL)
=V1= 2.25 mL /15 M
=0.15 mL
Therefore, the student must add 0.15 mL of solution to water using
Transcribed Image Text:30 ml of 0.075 M sodium chloride solution from a 15 M stock solution = C1 x V1 = C2 x V2 = (15 M) (V1) = (0.075 M) (30 mL) =V1= 2.25 mL /15 M =0.15 mL Therefore, the student must add 0.15 mL of solution to water using
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