3. Consider the digits of your student number 20XY-FAITH. The wooden block (mass m = 3.0729 kg) is released from rest at A by a compressed spring (compressed length 0.6 m, undeformed length 1 m, spring constant k = 150 N/m). The block is allowed to slide through the rough horizontal surface (A to B), then along the smooth circular ramp (B to C, central angle 0 = 41.5 °), until the block is released after point C. Calculate the speed of the block at points B and C. Also, what is the magnitude of the normal force exerted to the block just before the block leaves the ramp? Neglect the geometry of the block. NOTE: Use Work-Energy Method to solve for the speeds, and use FMA Method to compute for the normal force. 0.6 m amm 3.0729 kg A 1 m rough surface Hs = 0.35 Hk = 0.25 path of the block 1.5 m O B smooth surface Ꮎ 1.5 m C

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m = 3.0729
3. Consider the digits of your student number 20XY-FAITH. The wooden block (mass
kg) is released from rest at A by a compressed spring (compressed
length 0.6 m, undeformed length 1 m, spring constant k = 150 N/m). The block is allowed
to slide through the rough horizontal surface (A to B), then along the smooth circular ramp
(B to C, central angle 0 = 41.5 °), until the block is released after point C. Calculate
the speed of the block at points B and C. Also, what is the magnitude of the normal force
exerted to the block just before the block leaves the ramp? Neglect the geometry of the
block. NOTE: Use Work-Energy Method to solve for the speeds, and use FMA Method to
compute for the normal force.
0.6 m
mmmmm
3.0729 kg
A
1 m
rough surface
Hs = 0.35
Mk = 0.25
path of the block
1.5 m
O
B
smooth surface
Ө
1.5 m
C
Transcribed Image Text:m = 3.0729 3. Consider the digits of your student number 20XY-FAITH. The wooden block (mass kg) is released from rest at A by a compressed spring (compressed length 0.6 m, undeformed length 1 m, spring constant k = 150 N/m). The block is allowed to slide through the rough horizontal surface (A to B), then along the smooth circular ramp (B to C, central angle 0 = 41.5 °), until the block is released after point C. Calculate the speed of the block at points B and C. Also, what is the magnitude of the normal force exerted to the block just before the block leaves the ramp? Neglect the geometry of the block. NOTE: Use Work-Energy Method to solve for the speeds, and use FMA Method to compute for the normal force. 0.6 m mmmmm 3.0729 kg A 1 m rough surface Hs = 0.35 Mk = 0.25 path of the block 1.5 m O B smooth surface Ө 1.5 m C
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