3. A line has a slope of 4 and a y-intercept of 3. Find a vector equation of the line. a) [x, y] = [0,3] + [[1,4] Work: c) [x, y] = [3,0] + t[1,4] b) [x, y] = [− 1, - 4] + [[0,3] d) [x, y] = [0,3] + [[4,1] 4. Write the scalar equation of the plane with normal vector n = the point (6, 5, 4). - [2, 2, 5] and passing through a) 2x + 2y 5z+ 2 = 0 c) 2x+2y5z - 2 = 0 Work: b) 6x+5y4z + 2 = 0 - d) 6x+5y 4z − 2 = 0 -

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 21E
Question

PLS HELP ON ALL ASKED QUESTIONS PLS

3. A line has a slope of 4 and a y-intercept of 3. Find a vector equation of the line.
a) [x, y] = [0,3] + [[1,4]
Work:
c) [x, y] = [3,0] + t[1,4]
b) [x, y] = [− 1, - 4] + [[0,3]
d) [x, y] = [0,3] + [[4,1]
4. Write the scalar equation of the plane with normal vector n =
the point (6, 5, 4).
-
[2, 2, 5] and passing through
a) 2x + 2y
5z+ 2 = 0
c) 2x+2y5z
-
2 = 0
Work:
b) 6x+5y4z + 2 = 0
-
d) 6x+5y 4z − 2 = 0
-
Transcribed Image Text:3. A line has a slope of 4 and a y-intercept of 3. Find a vector equation of the line. a) [x, y] = [0,3] + [[1,4] Work: c) [x, y] = [3,0] + t[1,4] b) [x, y] = [− 1, - 4] + [[0,3] d) [x, y] = [0,3] + [[4,1] 4. Write the scalar equation of the plane with normal vector n = the point (6, 5, 4). - [2, 2, 5] and passing through a) 2x + 2y 5z+ 2 = 0 c) 2x+2y5z - 2 = 0 Work: b) 6x+5y4z + 2 = 0 - d) 6x+5y 4z − 2 = 0 -
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