23. What is the concentration (by mass) of the solute in a 25 °C solution prepared by dissolving 2.50x10 mol Na3PO4 in 1.000L of water (in ppm, ppb, and ppt, all to two decimal places)? A: 4.00 x 10- ppm; 4.10 × 10' ppb; 4.10×10* ppt

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23. What is the concentration (by mass) of the solute in a 25 °C solution prepared by dissolving
2.50x10 mol Na PO4 in 1.000 L of water (in ppm, ppb, and ppt, all to two decimal places)?
ppm; 4.10 × 10' ppb; 4.10×10* ppt
A: 4.00 × 10
Transcribed Image Text:23. What is the concentration (by mass) of the solute in a 25 °C solution prepared by dissolving 2.50x10 mol Na PO4 in 1.000 L of water (in ppm, ppb, and ppt, all to two decimal places)? ppm; 4.10 × 10' ppb; 4.10×10* ppt A: 4.00 × 10
Expert Solution
Step 1

According to question 

No. Of moles = 2.50× 10-7 

Volume = 1L 

So, Molarity = no. Of moles/Volume(L) 

                      = 2.50×10-7 /1 = 2.50×10-7 

Mass percentage =

              Mass of solute/Mass of solution ×100

Mass of solute = 2.50×10-⁷ × 163.941 (molar mass of Na3PO)

                          = 4.098×10-⁵ g 

Mass of solution = mass of solvent + water 

         = 4.098×10-⁵ + 1000 = 1000.00004g  (density of water taken as 1g/ml) 

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