Please answer ASAP. Ross and Rachel are fighting if they were on a break. Ross is trying to get his stuff weighing 150. N placed on an inclined plane by pulling it upwardsparallel to the inclined plane with 150. N force. However, Rachel is trying to stop Ross by exerting 50.0 N perpendicular to the inclined plane. Thecoefficients of friction between the box and the incline are us = 0.450 and uk = 0.350.50 NF·R·I·E·N·D·S30°150 N 2. Which of the following shows the correct equilibrium equation in the direction parallel to the inclined surface?A. EF = 150- W sin(30) - f + 50sin (30) = 0B. EF = 150-W cos(30) + N-f=0C. EF = 150-W cos(30) - f = 0D. EF = 150-W sin(30) - f = 0

Force applied by Ross parallel to inclined plane=150N Force applied by Rachel normal to inclined…

2. Which of the following shows the correct equilibrium equation in the direction parallel to the inclined surface? A. EF = 150- W sin(30) - f + 50sin (30) = 0 B. EF = 150-W cos(30) + N-f=0 C. EF = 150-W cos(30) - f = 0 D. EF = 150-W sin(30) - f = 0

2. Which of the following shows the correct equilibrium equation in the direction parallel to the inclined surface? A. EF = 150- W sin(30) - f + 50sin (30) = 0 B. EF = 150-W cos(30) + N-f=0 C. EF = 150-W cos(30) - f = 0 D. EF = 150-W sin(30) - f = 0

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Question

Please answer ASAP.

Ross and Rachel are fighting if they were on a break. Ross is trying to get his stuff weighing 150. N placed on an inclined plane by pulling it upwards
parallel to the inclined plane with 150. N force. However, Rachel is trying to stop Ross by exerting 50.0 N perpendicular to the inclined plane. The
coefficients of friction between the box and the incline are us = 0.450 and uk = 0.350.
50 N
F·R·I·E·N·D·S
30°
150 N

2. Which of the following shows the correct equilibrium equation in the direction parallel to the inclined surface?
A. EF = 150- W sin(30) - f + 50sin (30) = 0
B. EF = 150-W cos(30) + N-f=0
C. EF = 150-W cos(30) - f = 0
D. EF = 150-W sin(30) - f = 0

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