110m 100m 90m yellow green blue orange scale .1km.. 90m 60m river mouth 72m Let: Blue line = Basin length Determine the Form Factor (3 decimal places only) Determine the Elongation Ratio (3 decimal places only) Determine the Circularity Ratio (3 decimal places only)

3. Complete the table and sketch the traverse, assuming no measurements were obtained for line EF. LATITUDE DEPARTURE LINE LENGTH, m BEARING N (+) S() E(+) W(-) АВ N 5°30'8.33" E 490.71 47.27 BC 587.12 608.89 CD 327.41 786.78 DE 1002.76 218.32 EF FA 375.01 544.64 SUM

PROBLEM 1. Given in the accompanying tabulation are the adjusted latitude and adjusted departure of a closed traverse. Calculate the area by the DMD method LINE ADJ ADJ LAT DEP AB - 125.055 + 196.387 BC +20.241 + 241.003 CD +180.107 + 65.326 DE +210.169 - 104.519 EF -74.003 - 260.516 FA - 211.459 - 137.681

Problem 2: Locate the centroid ỹ of the area. 1 m -2 m-

x2 The asymptote of the hyperbola given by 1 has the equation 9 4 2х- Зу %3D0 Зх - 2у %3D 0 O A. В. 2х - у %3D 0 2x + y = 0 C. D.

AREA MEASUREMENTS W- E U AREA BY DOUBLE MERIDIAN DISTANCE (DMD) Problem 1: In the tabulation are given the adjusted latitudes and adjusted departures of a closed traverse. V Determine the area using DMD method. LINE ADJUSTED LATITUDE ADJUSTED DEPARTURE (+)N (-)S (+)E (-)W Y AB 113.92 388.84 ВС 178.86 285.13 CD 295.88 134.96 DE 164.35 135.39 EF 13.53 251.86 FA 182.95 151.76 SUM +474.74 -474.74 +673.97 -673.97

. Problem 1 Compute the area within the following traverse using the Coordinate method and CHECK by the DMDS method Balanced Coordinates Course Dep Lat Point X Y AB -226.9846 98.7106 A 709,489.434 709,262.449 709,176.011 709,061.165 709,361.616 708,846.452 G 709,568.788 709,682.105 I 709,563.827 121,072.089 121,170.800 120,992.637 120,797.489 120,807.032 120,287.159 120,244.663 119,715.939 120,610.402 BC -86.4386 -178.1623 CD -114.8457 -195.1486 C DE 300.4512 9.5436 EF -515.1646 -519.8733 日 FG 722.3360 -42.4958 F GH 113.3175 -528.7245 HI -118.2782 894.4631 IA -74.3929 461.6870

Q3: A: Draw the diagram of traverse classification. B: In closed traverse ABCD. The partial coordinates were known as shown below. Determine its area by DMD method. 04 N Dofland OWODY dienstl it with (nm) dinostim Mem. AB BC CD DA ΔΧ 40 -80 -50 AY 60 100 -70

The numerical value of departure equals the difference between the X coordinates of A and B, i.e. the increment AxAB, while the numerical value of latitude equals the difference between the Y coordinates of A and B, i.e. the increment AYAB- grid azimuth The horizontal distance DAB and the AAB can be computed. Ar - Xg - XxA Ay AB = Ys - YA D - Jar, + Ay Ay Ar AB AB = arctan AB AB

QA closed loop traverses was carried out during your practical session in the compus the observed data is as shown in table (1) of the coordinates station (1) are (5000.00MW) 5000M, E) and the bearing from Station (1) to (9) is (16⁰, 28' 60") calculate (A) the linear misclosure stations (B) the final coordinates 2, 3, 4, 5, 6, 7, 8, 9 of