1. Consider a Nd:YAG laser that is pumped with a diode laser. The configuration of this laser is shown below. Diode laser input Nd:YAG rod 1 cm Back mirror Reflectivity=1 Radius of curvature = infinity 5 cm The internal loss is 5% per pass. a. Calculate the small signal threshold gain (7th) for this laser. b. Now calculate the threshold power (Pth). where R₁ and R₂ are the radii of curvature. o = 2.8 x 10-20 cm² T=230 μs Curved mirror Reflectivity=0.95 Radius of curvature=10 cm Pth=1 ln(_1__) (npd ) ( hump ) ( 7 ( 10,2² +0₂²)) 2 R₁R₂ T²2² T 20 take 0,= p = 130 µm npd =n+] Ma Mpq The energy of the upper laser level is 11417 cm³¹. See Fig.10.5 in the text. c. What is the reason for the external curved mirror instead of using the back end of the crystal as the second mirror?
1. Consider a Nd:YAG laser that is pumped with a diode laser. The configuration of this laser is shown below. Diode laser input Nd:YAG rod 1 cm Back mirror Reflectivity=1 Radius of curvature = infinity 5 cm The internal loss is 5% per pass. a. Calculate the small signal threshold gain (7th) for this laser. b. Now calculate the threshold power (Pth). where R₁ and R₂ are the radii of curvature. o = 2.8 x 10-20 cm² T=230 μs Curved mirror Reflectivity=0.95 Radius of curvature=10 cm Pth=1 ln(_1__) (npd ) ( hump ) ( 7 ( 10,2² +0₂²)) 2 R₁R₂ T²2² T 20 take 0,= p = 130 µm npd =n+] Ma Mpq The energy of the upper laser level is 11417 cm³¹. See Fig.10.5 in the text. c. What is the reason for the external curved mirror instead of using the back end of the crystal as the second mirror?
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Transcribed Image Text:1. Consider a Nd:YAG laser that is pumped with a diode laser. The configuration of this laser is
shown below.
Diode laser
input
Nd:YAG rod
1 cm
5 cm
Back mirror
Reflectivity=1
Radius of curvature = infinity
Curved mirror
Reflectivity=0.95
Radius of curvature=10 cm
The internal loss is 5% per pass.
a. Calculate the small signal threshold gain (yn) for this laser.
b. Now calculate the threshold power (Pth).
Pth =1 In(_ 1_) (Npd)_( hvmp ) ( 1 ( m,²
2 R¡R2 T
+
20
where
Rị and R2 are the radii of curvature.
o = 2.8 x 10 20 cm?
t = 230 µs
take o, = mp = 130 µm
Npd = Nr Ni Na Npq
The energy of the upper laser level is 11417 cm". See Fig.10.5 in the text.
c. What is the reason for the external curved mirror instead of using the back end of the crystal
as the second mirror?
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