1. An AISI 1018 steel has a yield strength, Sy = 295 MPa. Using the distortion energy theory for the plane stress state ox = -30 MPs, Gy = -65 MPa, and Txy = 40 MPa. 1) Determine the factor of safety. 2) Plot the safety envelope of the material. 3) Plot the load line. 4) Estimate the factor of safety by graphical method (refer to 4-1 Ductile Failure I, P10).

1. An AISI 1018 steel has a yield strength, Sy = 295 MPa. Using the distortion energy theory for the plane stress state ox = -30 MPs, Gy = -65 MPa, and Txy = 40 MPa. 1) Determine the factor of safety. 2) Plot the safety envelope of the material. 3) Plot the load line. 4) Estimate the factor of safety by graphical method (refer to 4-1 Ductile Failure I, P10).

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.7.10P: Three round, copper alloy bars having the same length L but different shapes are shown, in the...

See similar textbooks

Similar questions

Three round, copper alloy bars having the same length L but different shapes are shown, in the figure. The first bar has a diameter d over its entire length, the second has a diameter d over one-fifth of its length, and the third has a diameter d over one-fifteenth of its length. Elsewhere, the second and third bars have a diameter Id. All three bars are subjected to the same axial load P. Use the following numerical data: P = 1400 kN, L = 5m,d= 80 mm, E= 110 GPa. and v = 0.33. (a) Find the change in length of each bar. (b) Find the change in volume of each bar.
A high-strength steel bar used in a large crane has a diameter d = 2.00 in. (sec figure). The steel has a modulus of elasticity E = 29 × 10 psi and Poisson’s ratio is v = 0.29. Because of clearance requirements, the diameter of the bar is limited to 2.001 in. when it is compressed by axial forces. What is the largest compressive load Pmaxthat is permitted?
Q2/ A steel bolt 0.005 m² in cross-section is subjected to a Static mean load of load of 200KN. What Value of Completely reversed direct fatigue load will Produce failure in 10² Cycles? Use the GERBER relationsip and assume that the Yield sureg. Strength of the steel is 400 MN/M² and the Stress required to produce. failure at 107 Cycles under Zero mean stress Condition is 300 MN/m².
a) A bar of normalized AISI 4130 is subjected to a steady torsional stress of 103 MPa, an alternating torsional stress of 69 MPa, and alternating bending stress of 83 MPa. It has an endurance limit of 276 MPa. Using Gerber and ASME-elliptic criteria, find the safety factors guarding against a fatigue failure and the expected life of the part. Analyse your results. b) A bar of 25 mm diameter cold-drawn SAE 1045 steel is loaded in rotating bending. Determine its endurance limit or strength.
1) Find the factor of fatigue safety using Goodman failure criterion
The fluctuating stresses listed in the table are found at a critical location of a component made of steel with Se = 40 ksi, Sy = 80 ksi, Sut = 110 ksi and f= 0.87. These stresses are applied on the part within 10 s. What is the accumulative damage of this part? What is the life of the part in hours if this stress pattern continues to repeat for the remained of the part's life? Use Goodman criterion and Miner's rule in your solution. Loading order |Omin o max |Number of cycles -20 30 -10 50 1 3. -30 30 1
2. In the stress-strain curve for steel shown below, identify following stresses in ksi and write their values in the space below: 2.1. Yield Point: ksi 2.2. Ultimate Tensile Strength: ksi 60- 400 350 50 300 E 40 250 30 200 150 20 100- 10 50 0. Strain, in/in or m/m J stv A Aa Stress, MPa Stress, ksi
A cylindrical steel bar 8 mm in diameter is loaded 1000 cycles per day with a load of 15560 N. How long until fatigue failure takes place? Note: stress force/area 500 450 400 350 Steel Allby 300 250 200 150 Brass Alloy 100 50 1.00E-07 Cycles to Failure, N 1.00E+04 1.00E+05 1.00E-06 1.00E+08 100E+09 1.00E+10 , The bar should not fatigue. ) The bar will fail in one cycle. ) 100 days ) 1000 days Stress Amplitude, MPa
Question 1 A bar of steel bar transmits a steady torsion of 30 kpsi while being subjected to an alternating bending stress of 45 kpsi. The material properties are given as Se 50 kpsi, Sy= 72 kpsi, and Sut= 85 kpsi. Find the factor of safety guarding against fatigue failure. For the fatigue analysis use: Modified Goodman criterion.
1. A part made of Aluminum 6061-T6 has a yield strength = 400 MPa. For each stress state below, draw all 3 Mohr's circles, find the principal stresses, and calculate the safety factor against yield using both the distortion-energy (von Mises) and maximum shear stress (Tresca) criterions. (If relevant) A clearly labeled diagram (or diagrams) clearly pertaining to your analysis with a coordinate system and relevant labels. Final answer with appropriate units and significant figures. You can use the fprintf() command in MATLAB to format numerical results A 2-3 sentence reflection on your answer. Does it make sense? Why or why not? What are some implications?
2. Another cylindrical component is madeof Enfennering ceramic Al203 but with different dimensions. Here, l=30 cm and the diameter is 4 cm. Assume the same Weibull modulus of 9. Calculate the level of the tensile strength for the following probability of failures: a. Pr (V) = 0.1 b. Pr (Vo) = 0.01 c. What is the survival probability and the failure probability of this component if a stress of 200 MPa is applied?
Define the rigid body used in statics. According to this; rigidity of bolt-nut connected elementBased on the value, the bolt diameter is 20 mm and the safe value of the bolt material.Calculate the stiffness values of the bolt and the intermediate element plate. (Note: Bolt's9x10 ^ 2 times as stress value ??? / cm ^ 2take as.). Strain gaugeElongation in bolt length measured with 250 ??, shortening amount in intermediate element platesIt was measured at 125 ??.