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- The heat of neutralization, Hneut, can be defined as the amount of heat released (or absorbed), q, per mole of acid (or base) neutralized. Hneut for nitric acid is -52 kJ/mol HNO3. At 27.3C, 50.00 mL of 0.743M HNO3 is neutralized by 1.00 M Sr(OH)2 in a coffee-cup calorimeter. (a) How many mL of Sr(OH)2 were used in the neutralization? (b) What is the final temperature of the resulting solution? (Use the assumptions in Question 11.)O-H H CH,OH (b) CH2 CH, NH, H--0=C (b) 0-H-- (a) CH, CH, CH, CH H-C CH, (CH.)4–NH, CH, CH, |(d) (a) CH, (d) (c) CH, CH, HC CH CH, CH,COOH (b) [The image above is from a different textbook. Ask me later if you would like to know the reference.] The image above depicts protein tertiary structure. What type of tertiary structure is represented by the letter (d) in the image? O hydrogen bonding 3 of these 4 responses are correct. O disulfide linkage O hydrophobic interaction salt bridge6) OH- heat ?
- 2. Write the expression for Kc and Kp if applicable, for the following reversible reactions at equilibrium: (a) HF(aq) + H;0() H,0 (aq) + F (aq) (b) 2NO(g) + 0,(g) 2NO0,(g) (C) CH,COOH(aq) + C,H,OH(aq) CH,C0OC,H,(aq) + H,O()(aq) (aq) BeSO, (aq) + H,O(1) ↑ 4.Why is it legitimate to neglect the term Kw/[H3O+] when f is small? , The original number of moles of acid is denoted by no.
- The proton donor in the reaction below is: * CH,COOHag) + H,0, → H,O^ (aq) + CH,CO ag) (1) CH;COOH O°H O O H,0" O CH,CO01Calculate AH for the reaction CH4 (g) + NH3 (g) → HCN (g) + 3 H2 (g), given: N2 (g) + 3 H2 (g) → 2 NH3 (g) C (s) + 2 H2 (g) → CH4 (g) H2 (g) + 2 C (s) + N2 (g) → 2 HCN (g) AH = -91.8 kJ AH = -74.9 kJ AH = 270.3 k %3Dered You want to determine the enthalpy change for the neutralization of HCI(aq). The equipment you are allowed to use are listed below: • safety goggles tion • lab coat • protective gloves • coffee cups (2) • styrofoam lid • thermometer • scale • stirring rod • beaker 16-ml of 0.345 mol/L HCI(a) added to 42.6-ml of NaOH (aq) for a total volume which is equivalent to water (m) in the q equation a. Based on the equipment provided above, design a lab to determine the enthalpy change of neutralization of HCI(aq). Ensure you use numbered steps. When you carry out the experiment, you observe a temperature change of 3.80°C. b. Calculate the quantity of heat transferred to the calorimeter based upon the data provided. c. Based upon the data provided, calculate the molar enthalpy for the neutralization of HCI(aq). d. If the mass of volume of the HCl(aq) was increased, would the value of Q be different. Explain your reasoning. e. Provide a thorough concluding statement that includes the…
- 이 O₂N Br NaOH, 80 °C then H3O+Based on the reactions: 2NO2 (g) + 2N0 (g) + O2 (g) – – > 2N½O4 (g) ; AH = -228.54 kJ 4NO (g) +2N2O (g) + 50, (5) – – > 4N,O4 (g) ; AH,=-488.46 kJ 2NO (g) + O2 (g) – - > N,O4 (g) ; AH3 = –171.34 kJ- Use Hess's Law to calculate AH for: 4N204 (g) - - > 2N½O (g) + 302 (9) + 4NO2 (g)[References] Calculate AH for the reaction: 2NH3 (g) + O2(g) → N2H4 (1) + H2O(1) given the following data: 2NH3 (g) + 3N2O(g) → 4N2(g) + 3H2O(1) AH =–1010. kJ N2O(9) + ЗH2(9) — N;Ha (1) + Hа0(1) ДН %3D — 317 kJ N2H4 (1) + O2 (9) → N2(g)+2H20(1) ΔΗ--623 k.J На (9) + О2(9) — Н,0(1) AH = -286 kJ ΔΗ- kJ Submit Answer Try Another Version 3 item attempts remaining